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A student says that if the denominator of a fraction in lowest terms has 5 as a factor, then its decimal expansion terminates. Which fraction disproves the statement?

Answer and explanation

Correct answer: \(\frac{7}{75}\)

Since \(75=3\times5^2\), the denominator of \(\frac{7}{75}\) contains 3, so its decimal expansion is non-terminating recurring. In contrast, \(40=2^3\times5\). Exam tip: a reduced fraction terminates only when its denominator has factors 2 and/or 5 only.

Related tags

Number SystemsRational NumbersDecimal ExpansionTerminating DecimalsRecurring DecimalsDenominator FactorsDecimal RepresentationMathematics

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