Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 91-100 of 600 questions.
What is \(a_6\) of the arithmetic progression \(16,20,24,28,\ldots\)?
C. (36)
(a=16) और (d=4), इसलिए \(a_6=16+5\times4=36\) है। परीक्षा में (n-1) को सही रखें। / (a=16) and (d=4), so \(a_6=16+5\times4=36\). In exams, keep (n-1) correct.
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If an arithmetic progression has \(a_1=9\) and (d=8), what is \(a_4\)?
C. (33)
\(a_4=9+3\times8=33\) है। परीक्षा में चौथे पद के लिए तीन अंतर जोड़ें। / \(a_4=9+3\times8=33\). In exams, add three differences for the fourth term.
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Which sequence has common difference (-6)?
B. (30,24,18,12)
(30,24,18,12) में हर बार (6) घटता है। परीक्षा में घटते अंतर को ऋणात्मक लिखें। / In (30,24,18,12), (6) is subtracted each time. In exams, write a decreasing difference as negative.
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What is the tenth term of the arithmetic progression \(9,18,27,36,\ldots\)?
C. (90)
यह (9) के गुणजों की श्रेणी है, इसलिए दसवाँ पद (90) है। परीक्षा में गुणजों को जल्दी पहचानें। / This is a sequence of multiples of (9), so the tenth term is (90). In exams, identify multiples quickly.
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If \(a_n=15-3n\), what is the value of \(a_4\)?
C. (3)
\(a_4=15-12=3\) है। परीक्षा में घटते नियम में (3n) सही घटाएँ। / \(a_4=15-12=3\). In exams, subtract (3n) correctly in a decreasing rule.
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What is the general term of the arithmetic progression \(12,9,6,3,\ldots\)?
B. \(a_n=15-3n\)
(n=1) पर (12) और (n=2) पर (9) मिलता है, इसलिए \(a_n=15-3n\) है। परीक्षा में पहला पद जाँचकर नियम चुनें। / At (n=1) it gives (12), and at (n=2) it gives (9), so \(a_n=15-3n\). In exams, choose the rule after checking the first term.
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If (8,,x,,20) is an arithmetic progression, what is the value of (x)?
C. (14)
बीच का पद (8) और (20) का औसत है, इसलिए \(x=\frac{8+20}{2}=14\) है। परीक्षा में तीन पदों वाली श्रेणी में मध्य पद का औसत लें। / The middle term is the average of (8) and (20), so \(x=\frac{8+20}{2}=14\). In exams, take the average for the middle term in three-term progressions.
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What will be the seventh term in the arithmetic progression \(20,26,32,38,\ldots\)?
D. (56)
(a=20) और (d=6), इसलिए \(a_7=20+6\times6=56\) है। परीक्षा में (n-1) बार अंतर जोड़ें। / (a=20) and (d=6), so \(a_7=20+6\times6=56\). In exams, add the difference (n-1) times.
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Which arithmetic progression has first term (9) and common difference (5)?
A. \(9,14,19,24,\ldots\)
पहला पद (9) है और हर बार (5) जुड़ रहा है। परीक्षा में पहला पद और अंतर दोनों मिलाएँ। / The first term is (9), and (5) is added each time. In exams, match both the first term and the difference.
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If (a=11) and (d=6), what will be the sixth term of the arithmetic progression?
C. (41)
छठा पद (a+5d=11+30=41) है। परीक्षा में (n)वें पद के लिए (n-1) बार अंतर जोड़ें। / The sixth term is (a+5d=11+30=41). In exams, add the difference (n-1) times for the (n)th term.
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