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Which arithmetic progression has first term (9) and common difference (5)?

Answer and explanation

Correct answer: (9,14,19,24,\ldots)

An arithmetic progression has a fixed common difference between consecutive terms. We need a sequence that begins with 9 and increases by 5 each time. Option A is 9, 14, 19, 24, and so on. The first term is 9, and the successive differences are \(14-9=5\), \(19-14=5\), and \(24-19=5\). Therefore it meets both conditions exactly.

The other choices do not. Option B begins with 5 rather than 9. Option C begins with 9, but it adds 9 each time, since \(18-9=9\), not 5. Option D has the required difference of 5 but begins with 14, not 9. Hence option A is the only valid answer. Always check both the starting term and the change between terms, because matching only one of them is insufficient.

Related tags

SequencesProgressionsArithmetic-ProgressionClass-9Easy

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