The perimeter is \(4\sqrt{7}\) and \(\sqrt{7}\) is irrational. A non-zero rational multiplier keeps irrationality.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय संख्या / Irrational number. The perimeter is \(4\sqrt{7}\) and \(\sqrt{7}\) is irrational. A non-zero rational multiplier keeps irrationality.
Step 3
Exam Tip
परिमाप \(4\sqrt{7}\) होगा और \(\sqrt{7}\) अपरिमेय है। शून्येतर परिमेय गुणक से अपरिमेयता बनी रहती है।
The side will be \(\sqrt{11}\) and (11) is not a perfect square. So \(\sqrt{11}\) is irrational.
Step 2
Why this answer is correct
The correct answer is D. अपरिमेय संख्या / Irrational number. The side will be \(\sqrt{11}\) and (11) is not a perfect square. So \(\sqrt{11}\) is irrational.
Step 3
Exam Tip
भुजा \(\sqrt{11}\) होगी और (11) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{11}\) अपरिमेय है।
The positive number is \(\sqrt{19}\) because (\(\sqrt{19}\)2=19). Since (19) is not a perfect square, it is irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{19}\). The positive number is \(\sqrt{19}\) because (\(\sqrt{19}\)2=19). Since (19) is not a perfect square, it is irrational.
Step 3
Exam Tip
धनात्मक संख्या \(\sqrt{19}\) है क्योंकि (\(\sqrt{19}\)2=19)। (19) पूर्ण वर्ग नहीं है इसलिए यह अपरिमेय है।
The positive number is \(\sqrt{37}\) because (\(\sqrt{37}\)2=37). Since (37) is not a perfect square, it is irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{37}\). The positive number is \(\sqrt{37}\) because (\(\sqrt{37}\)2=37). Since (37) is not a perfect square, it is irrational.
Step 3
Exam Tip
धनात्मक संख्या \(\sqrt{37}\) है क्योंकि (\(\sqrt{37}\)2=37)। (37) पूर्ण वर्ग नहीं है इसलिए यह अपरिमेय है।
