एक वर्ग की भुजा \(\sqrt{7}\) इकाई है। उसका परिमाप किस प्रकार की संख्या होगा?
The side of a square is \(\sqrt{7}\) units. What type of number will its perimeter be?
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A परिमेय संख्या / Rational number
B अपरिमेय संख्या / Irrational number
C पूर्णांक / Integer
D प्राकृतिक संख्या / Natural number
Explanation opens after your attempt
Correct Answer
B. अपरिमेय संख्या / Irrational number
Step 1
Concept
The perimeter is \(4\sqrt{7}\) and \(\sqrt{7}\) is irrational. A non-zero rational multiplier keeps irrationality.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय संख्या / Irrational number. The perimeter is \(4\sqrt{7}\) and \(\sqrt{7}\) is irrational. A non-zero rational multiplier keeps irrationality.
Step 3
Exam Tip
परिमाप \(4\sqrt{7}\) होगा और \(\sqrt{7}\) अपरिमेय है। शून्येतर परिमेय गुणक से अपरिमेयता बनी रहती है।
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किस दशमलव से अपरिमेय संख्या पहचानी जा सकती है?
Which decimal form can identify an irrational number?
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A सांत दशमलव / Terminating decimal
B असांत अनावर्ती दशमलव / Non-terminating non-repeating decimal
C आवर्ती दशमलव / Repeating decimal
D पूर्णांक दशमलव / Integer decimal
Explanation opens after your attempt
Correct Answer
B. असांत अनावर्ती दशमलव / Non-terminating non-repeating decimal
Step 1
Concept
An irrational number has a non-terminating and non-repeating decimal. In exams check the repeating part carefully.
Step 2
Why this answer is correct
The correct answer is B. असांत अनावर्ती दशमलव / Non-terminating non-repeating decimal. An irrational number has a non-terminating and non-repeating decimal. In exams check the repeating part carefully.
Step 3
Exam Tip
अपरिमेय संख्या का दशमलव असांत और अनावर्ती होता है। परीक्षा में दोहराने वाले भाग को ध्यान से देखें।
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यदि किसी वर्ग का क्षेत्रफल (11) वर्ग इकाई है तो उसकी भुजा किस प्रकार की संख्या होगी?
If the area of a square is (11) square units then what type of number will its side be?
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A परिमेय संख्या / Rational number
B पूर्णांक / Integer
C सांत दशमलव / Terminating decimal
D अपरिमेय संख्या / Irrational number
Explanation opens after your attempt
Correct Answer
D. अपरिमेय संख्या / Irrational number
Step 1
Concept
The side will be \(\sqrt{11}\) and (11) is not a perfect square. So \(\sqrt{11}\) is irrational.
Step 2
Why this answer is correct
The correct answer is D. अपरिमेय संख्या / Irrational number. The side will be \(\sqrt{11}\) and (11) is not a perfect square. So \(\sqrt{11}\) is irrational.
Step 3
Exam Tip
भुजा \(\sqrt{11}\) होगी और (11) पूर्ण वर्ग नहीं है। इसलिए \(\sqrt{11}\) अपरिमेय है।
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दशमलव \(2.5050050005\ldots\) किस प्रकार की संख्या है?
What type of number is the decimal \(2.5050050005\ldots\)?
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A परिमेय / Rational
B अपरिमेय / Irrational
C पूर्णांक / Integer
D सांत दशमलव / Terminating decimal
Explanation opens after your attempt
Correct Answer
B. अपरिमेय / Irrational
Step 1
Concept
It has no fixed repetition so it is irrational. Do not mistake a non-repeating pattern for a repeating one.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. It has no fixed repetition so it is irrational. Do not mistake a non-repeating pattern for a repeating one.
Step 3
Exam Tip
इसमें निश्चित दोहराव नहीं है इसलिए यह अपरिमेय है। अनावर्ती पैटर्न को आवर्ती मानने की गलती न करें।
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\(\sqrt{121}\) के बारे में सही कथन कौन-सा है?
Which statement is correct about \(\sqrt{121}\)?
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A यह अपरिमेय है / It is irrational
B यह परिमेय है / It is rational
C यह अनिर्धारित है / It is undefined
D यह ऋणात्मक है / It is negative
Explanation opens after your attempt
Correct Answer
B. यह परिमेय है / It is rational
Step 1
Concept
\(\sqrt{121}=11\) so it is rational. The square root of a perfect square is an integer.
Step 2
Why this answer is correct
The correct answer is B. यह परिमेय है / It is rational. \(\sqrt{121}=11\) so it is rational. The square root of a perfect square is an integer.
Step 3
Exam Tip
\(\sqrt{121}=11\) है इसलिए यह परिमेय है। पूर्ण वर्ग का वर्गमूल पूर्णांक होता है।
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इनमें से कौन-सा वर्गमूल अपरिमेय नहीं है?
Which square root is not irrational?
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A \(\sqrt{31}\)
B \(\sqrt{40}\)
C \(\sqrt{64}\)
D \(\sqrt{72}\)
Explanation opens after your attempt
Correct Answer
C. \(\sqrt{64}\)
Step 1
Concept
\(\sqrt{64}=8\) so it is rational. Square roots of perfect squares are not irrational.
Step 2
Why this answer is correct
The correct answer is C. \(\sqrt{64}\). \(\sqrt{64}=8\) so it is rational. Square roots of perfect squares are not irrational.
Step 3
Exam Tip
\(\sqrt{64}=8\) इसलिए यह परिमेय है। पूर्ण वर्गों के वर्गमूल अपरिमेय नहीं होते।
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यदि \(x=\sqrt{6}\) है तो (2x) किस प्रकार की संख्या है?
If \(x=\sqrt{6}\), what type of number is (2x)?
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A परिमेय / Rational
B पूर्णांक / Integer
C अपरिमेय / Irrational
D शून्य / Zero
Explanation opens after your attempt
Correct Answer
C. अपरिमेय / Irrational
Step 1
Concept
\(2x=2\sqrt{6}\), which is irrational. Multiplication by a non-zero rational keeps irrationality.
Step 2
Why this answer is correct
The correct answer is C. अपरिमेय / Irrational. \(2x=2\sqrt{6}\), which is irrational. Multiplication by a non-zero rational keeps irrationality.
Step 3
Exam Tip
\(2x=2\sqrt{6}\) होगा जो अपरिमेय है। शून्येतर परिमेय से गुणा करने पर अपरिमेयता बनी रहती है।
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\(\sqrt{3}\times\sqrt{27}\) का मान क्या है?
What is the value of \(\sqrt{3}\times\sqrt{27}\)?
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A (9)
B \(\sqrt{30}\)
C \(3\sqrt{3}\)
D \(\sqrt{81}\)
Explanation opens after your attempt
Step 1
Concept
\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). The product of two irrationals can be rational.
Step 2
Why this answer is correct
The correct answer is A. (9). \(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). The product of two irrationals can be rational.
Step 3
Exam Tip
\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\) होता है। दो अपरिमेयों का गुणनफल परिमेय हो सकता है।
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कौन-सी संख्या \(\sqrt{10}\) और \(\sqrt{11}\) के बीच निश्चित रूप से है?
Which number definitely lies between \(\sqrt{10}\) and \(\sqrt{11}\)?
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A (3)
B \(\sqrt{10.5}\)
C (4)
D \(\sqrt{9}\)
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{10.5}\)
Step 1
Concept
Since (10<10.5<11), \(\sqrt{10.5}\) lies between them. Compare square roots using the numbers inside.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{10.5}\). Since (10<10.5<11), \(\sqrt{10.5}\) lies between them. Compare square roots using the numbers inside.
Step 3
Exam Tip
क्योंकि (10<10.5<11), इसलिए \(\sqrt{10.5}\) दोनों के बीच है। वर्गमूल की तुलना अंदर की संख्याओं से करें।
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\(\sqrt{48}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{48}\)?
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A \(6\sqrt{2}\)
B \(8\sqrt{3}\)
C \(4\sqrt{3}\)
D (12)
Explanation opens after your attempt
Correct Answer
C. \(4\sqrt{3}\)
Step 1
Concept
\(\sqrt{48}=\sqrt{16\times3}=4\sqrt{3}\). Take the perfect-square factor outside.
Step 2
Why this answer is correct
The correct answer is C. \(4\sqrt{3}\). \(\sqrt{48}=\sqrt{16\times3}=4\sqrt{3}\). Take the perfect-square factor outside.
Step 3
Exam Tip
\(\sqrt{48}=\sqrt{16\times3}=4\sqrt{3}\) है। पूर्ण वर्ग गुणनखंड बाहर निकालें।
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यदि \(a=\sqrt{5}\) है तो \(a^2\) किस प्रकार की संख्या है?
If \(a=\sqrt{5}\), what type of number is \(a^2\)?
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A अपरिमेय / Irrational
B परिमेय / Rational
C अनिर्धारित / Undefined
D ऋणात्मक / Negative
Explanation opens after your attempt
Correct Answer
B. परिमेय / Rational
Step 1
Concept
(a-2 =\(\sqrt{5}\)2 =5), so it is rational. The square of an irrational can sometimes be rational.
Step 2
Why this answer is correct
The correct answer is B. परिमेय / Rational. (a-2 =\(\sqrt{5}\)2 =5), so it is rational. The square of an irrational can sometimes be rational.
Step 3
Exam Tip
(a-2 =\(\sqrt{5}\)2 =5) है इसलिए यह परिमेय है। अपरिमेय का वर्ग कभी-कभी परिमेय होता है।
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\(\frac{\sqrt{45}}{\sqrt{5}}\) का मान क्या है?
What is the value of \(\frac{\sqrt{45}}{\sqrt{5}}\)?
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A \(\sqrt{40}\)
B (5)
C (3)
D \(\sqrt{50}\)
Explanation opens after your attempt
Step 1
Concept
\(\frac{\sqrt{45}}{\sqrt{5}}=\sqrt{9}=3\). After simplification the result can be rational.
Step 2
Why this answer is correct
The correct answer is C. (3). \(\frac{\sqrt{45}}{\sqrt{5}}=\sqrt{9}=3\). After simplification the result can be rational.
Step 3
Exam Tip
\(\frac{\sqrt{45}}{\sqrt{5}}=\sqrt{9}=3\) है। सरलीकरण के बाद परिणाम परिमेय हो सकता है।
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\(\sqrt[3]{27}\) किस प्रकार की संख्या है?
What type of number is \(\sqrt[3]{27}\)?
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A अपरिमेय / Irrational
B परिमेय / Rational
C अनावर्ती दशमलव / Non-repeating decimal
D अनिर्धारित / Undefined
Explanation opens after your attempt
Correct Answer
B. परिमेय / Rational
Step 1
Concept
\(\sqrt[3]{27}=3\) so it is rational. The cube root of a perfect cube is rational.
Step 2
Why this answer is correct
The correct answer is B. परिमेय / Rational. \(\sqrt[3]{27}=3\) so it is rational. The cube root of a perfect cube is rational.
Step 3
Exam Tip
\(\sqrt[3]{27}=3\) है इसलिए यह परिमेय है। पूर्ण घन का घनमूल परिमेय होता है।
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\(\sqrt[3]{5}\) के बारे में सही कथन चुनिए।
Choose the correct statement about \(\sqrt[3]{5}\).
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A यह परिमेय है / It is rational
B यह पूर्णांक है / It is an integer
C यह अपरिमेय है / It is irrational
D यह शून्य है / It is zero
Explanation opens after your attempt
Correct Answer
C. यह अपरिमेय है / It is irrational
Step 1
Concept
(5) is not a perfect cube so \(\sqrt[3]{5}\) is irrational. In cube roots check perfect cubes.
Step 2
Why this answer is correct
The correct answer is C. यह अपरिमेय है / It is irrational. (5) is not a perfect cube so \(\sqrt[3]{5}\) is irrational. In cube roots check perfect cubes.
Step 3
Exam Tip
(5) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{5}\) अपरिमेय है। घनमूल में पूर्ण घन देखना चाहिए।
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इनमें से कौन-सा (1) और (3) के बीच अपरिमेय है?
Which of these is irrational between (1) and (3)?
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A \(\sqrt{9}\)
B \(\sqrt{5}\)
C (2)
D (2.5)
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{5}\)
Step 1
Concept
\(\sqrt{5}\) lies between (1) and (3) and is irrational. Estimate using nearby perfect squares.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{5}\). \(\sqrt{5}\) lies between (1) and (3) and is irrational. Estimate using nearby perfect squares.
Step 3
Exam Tip
\(\sqrt{5}\) का मान (1) और (3) के बीच है और यह अपरिमेय है। निकट पूर्ण वर्गों से अनुमान लगाएं।
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\(6-\sqrt{2}\) किस प्रकार की संख्या है?
What type of number is \(6-\sqrt{2}\)?
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A परिमेय / Rational
B पूर्णांक / Integer
C अपरिमेय / Irrational
D शून्य / Zero
Explanation opens after your attempt
Correct Answer
C. अपरिमेय / Irrational
Step 1
Concept
Subtracting irrational \(\sqrt{2}\) from rational (6) gives an irrational number. The irrational part does not disappear.
Step 2
Why this answer is correct
The correct answer is C. अपरिमेय / Irrational. Subtracting irrational \(\sqrt{2}\) from rational (6) gives an irrational number. The irrational part does not disappear.
Step 3
Exam Tip
परिमेय (6) में से अपरिमेय \(\sqrt{2}\) घटाने पर अपरिमेय संख्या मिलती है। अपरिमेय भाग खत्म नहीं होता।
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\(\sqrt{7}+\sqrt{7}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{7}+\sqrt{7}\)?
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A \(2\sqrt{7}\)
B \(\sqrt{14}\)
C (7)
D (14)
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{7}\)
Step 1
Concept
Adding like radicals gives \(2\sqrt{7}\). It is irrational because \(\sqrt{7}\) remains.
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{7}\). Adding like radicals gives \(2\sqrt{7}\). It is irrational because \(\sqrt{7}\) remains.
Step 3
Exam Tip
समान मूलों को जोड़ने पर \(2\sqrt{7}\) मिलता है। यह अपरिमेय है क्योंकि \(\sqrt{7}\) बचता है।
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\(\sqrt{12}+\sqrt{75}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{12}+\sqrt{75}\)?
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A \(7\sqrt{3}\)
B \(9\sqrt{3}\)
C \(5\sqrt{3}\)
D \(\sqrt{87}\)
Explanation opens after your attempt
Correct Answer
A. \(7\sqrt{3}\)
Step 1
Concept
\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\), so the sum is \(7\sqrt{3}\). Simplify both radicals first.
Step 2
Why this answer is correct
The correct answer is A. \(7\sqrt{3}\). \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\), so the sum is \(7\sqrt{3}\). Simplify both radicals first.
Step 3
Exam Tip
\(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{75}=5\sqrt{3}\), इसलिए योग \(7\sqrt{3}\) है। पहले दोनों मूल सरल करें।
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\(\sqrt{80}-\sqrt{45}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{80}-\sqrt{45}\)?
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A \(\sqrt{35}\)
B \(5\sqrt{5}\)
C \(\sqrt{5}\)
D \(4\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
C. \(\sqrt{5}\)
Step 1
Concept
\(\sqrt{80}=4\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\), so the difference is \(\sqrt{5}\). Subtract like radicals.
Step 2
Why this answer is correct
The correct answer is C. \(\sqrt{5}\). \(\sqrt{80}=4\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\), so the difference is \(\sqrt{5}\). Subtract like radicals.
Step 3
Exam Tip
\(\sqrt{80}=4\sqrt{5}\) और \(\sqrt{45}=3\sqrt{5}\), इसलिए अंतर \(\sqrt{5}\) है। समान मूलों को घटाएं।
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\(\frac{5}{\sqrt{5}}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\frac{5}{\sqrt{5}}\)?
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A \(5\sqrt{5}\)
B \(\sqrt{5}\)
C (1)
D (25)
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{5}\)
Step 1
Concept
\(\frac{5}{\sqrt{5}}=\sqrt{5}\). Simplify carefully when the denominator has a radical.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{5}\). \(\frac{5}{\sqrt{5}}=\sqrt{5}\). Simplify carefully when the denominator has a radical.
Step 3
Exam Tip
\(\frac{5}{\sqrt{5}}=\sqrt{5}\) होता है। हर में मूल हो तो सरलीकरण ध्यान से करें।
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\(\frac{1}{\sqrt{3}}\) को हर में मूल हटाकर कैसे लिखा जा सकता है?
How can \(\frac{1}{\sqrt{3}}\) be written after removing the radical from the denominator?
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A \(\frac{\sqrt{3}}{3}\)
B \(\frac{3}{\sqrt{3}}\)
C \(3\sqrt{3}\)
D \(\sqrt{6}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{\sqrt{3}}{3}\)
Step 1
Concept
Multiplying \(\frac{1}{\sqrt{3}}\) by \(\frac{\sqrt{3}}{\sqrt{3}}\) gives \(\frac{\sqrt{3}}{3}\). This is called rationalising the denominator.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{\sqrt{3}}{3}\). Multiplying \(\frac{1}{\sqrt{3}}\) by \(\frac{\sqrt{3}}{\sqrt{3}}\) gives \(\frac{\sqrt{3}}{3}\). This is called rationalising the denominator.
Step 3
Exam Tip
\(\frac{1}{\sqrt{3}}\) को \(\frac{\sqrt{3}}{\sqrt{3}}\) से गुणा करने पर \(\frac{\sqrt{3}}{3}\) मिलता है। इसे हर का परिमेयकरण कहते हैं।
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कौन-सा विकल्प परिमेय संख्या है?
Which option is a rational number?
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A \(\sqrt{29}\)
B \(\sqrt{2}+1\)
C \(\pi\)
D \(0.454545\ldots\)
Explanation opens after your attempt
Correct Answer
D. \(0.454545\ldots\)
Step 1
Concept
\(0.454545\ldots\) is repeating so it is rational. A repeating decimal can be converted into a fraction.
Step 2
Why this answer is correct
The correct answer is D. \(0.454545\ldots\). \(0.454545\ldots\) is repeating so it is rational. A repeating decimal can be converted into a fraction.
Step 3
Exam Tip
\(0.454545\ldots\) आवर्ती दशमलव है इसलिए परिमेय है। आवर्ती दशमलव को भिन्न में बदला जा सकता है।
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\(\pi+2\) किस प्रकार की संख्या है?
What type of number is \(\pi+2\)?
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A परिमेय / Rational
B अपरिमेय / Irrational
C पूर्णांक / Integer
D सांत दशमलव / Terminating decimal
Explanation opens after your attempt
Correct Answer
B. अपरिमेय / Irrational
Step 1
Concept
\(\pi\) is irrational and (2) is rational, so the sum is irrational. Do not treat \(\pi\) as equal to (22/7).
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. \(\pi\) is irrational and (2) is rational, so the sum is irrational. Do not treat \(\pi\) as equal to (22/7).
Step 3
Exam Tip
\(\pi\) अपरिमेय है और (2) परिमेय है, इसलिए योग अपरिमेय है। \(\pi\) को (22/7) के बराबर न मानें।
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(22/7) के बारे में सही कथन कौन-सा है?
Which statement is correct about (22/7)?
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A यह \(\pi\) का निकट मान है / It is an approximation of \(\pi\)
B यह अपरिमेय है / It is irrational
C यह \(\pi\) के बिल्कुल बराबर है / It is exactly equal to \(\pi\)
D यह पूर्णांक है / It is an integer
Explanation opens after your attempt
Correct Answer
A. यह \(\pi\) का निकट मान है / It is an approximation of \(\pi\)
Step 1
Concept
(22/7) is rational and an approximation of \(\pi\). Do not treat an approximation as exact equality.
Step 2
Why this answer is correct
The correct answer is A. यह \(\pi\) का निकट मान है / It is an approximation of \(\pi\). (22/7) is rational and an approximation of \(\pi\). Do not treat an approximation as exact equality.
Step 3
Exam Tip
(22/7) परिमेय है और \(\pi\) का निकट मान है। निकट मान को वास्तविक बराबरी न समझें।
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यदि किसी संख्या का दशमलव \(4.10110111011110\ldots\) है, तो वह कैसी है?
If a number has decimal \(4.10110111011110\ldots\), what is it?
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A परिमेय / Rational
B अपरिमेय / Irrational
C पूर्णांक / Integer
D सांत / Terminating
Explanation opens after your attempt
Correct Answer
B. अपरिमेय / Irrational
Step 1
Concept
This decimal is non-terminating and non-repeating so it is irrational. There is no fixed repeating block.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. This decimal is non-terminating and non-repeating so it is irrational. There is no fixed repeating block.
Step 3
Exam Tip
यह दशमलव असांत और अनावर्ती है इसलिए अपरिमेय है। निश्चित दोहराने वाला ब्लॉक नहीं है।
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\(\sqrt{\frac{16}{25}}\) किसके बराबर है?
What is \(\sqrt{\frac{16}{25}}\) equal to?
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A \(\frac{8}{5}\)
B \(\frac{4}{5}\)
C \(\frac{16}{25}\)
D \(\frac{5}{4}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{4}{5}\)
Step 1
Concept
\(\sqrt{\frac{16}{25}}=\frac{4}{5}\), so it is rational. Both numerator and denominator are perfect squares.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{4}{5}\). \(\sqrt{\frac{16}{25}}=\frac{4}{5}\), so it is rational. Both numerator and denominator are perfect squares.
Step 3
Exam Tip
\(\sqrt{\frac{16}{25}}=\frac{4}{5}\) है इसलिए यह परिमेय है। अंश और हर दोनों पूर्ण वर्ग हैं।
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\(\sqrt{\frac{7}{4}}\) किस प्रकार की संख्या है?
What type of number is \(\sqrt{\frac{7}{4}}\)?
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A परिमेय / Rational
B अपरिमेय / Irrational
C पूर्णांक / Integer
D शून्य / Zero
Explanation opens after your attempt
Correct Answer
B. अपरिमेय / Irrational
Step 1
Concept
\(\sqrt{\frac{7}{4}}=\frac{\sqrt{7}}{2}\) and \(\sqrt{7}\) is irrational. Check perfect squares even in fractions.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. \(\sqrt{\frac{7}{4}}=\frac{\sqrt{7}}{2}\) and \(\sqrt{7}\) is irrational. Check perfect squares even in fractions.
Step 3
Exam Tip
\(\sqrt{\frac{7}{4}}=\frac{\sqrt{7}}{2}\) है और \(\sqrt{7}\) अपरिमेय है। भिन्न में भी पूर्ण वर्ग जाँचें।
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\(10\sqrt{2}\div5\) का सरल रूप क्या है?
What is the simplified form of \(10\sqrt{2}\div5\)?
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A \(2\sqrt{2}\)
B \(5\sqrt{2}\)
C \(10\sqrt{10}\)
D (\sqrt{2} / 5)
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{2}\)
Step 1
Concept
\(10\sqrt{2}\div5=2\sqrt{2}\), which is irrational. Simplify the numerical coefficient separately.
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{2}\). \(10\sqrt{2}\div5=2\sqrt{2}\), which is irrational. Simplify the numerical coefficient separately.
Step 3
Exam Tip
\(10\sqrt{2}\div5=2\sqrt{2}\) है जो अपरिमेय है। संख्यात्मक गुणांक को अलग सरल करें।
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\(-3\sqrt{11}\) किस प्रकार की संख्या है?
What type of number is \(-3\sqrt{11}\)?
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A परिमेय / Rational
B अपरिमेय / Irrational
C प्राकृतिक / Natural
D शून्य / Zero
Explanation opens after your attempt
Correct Answer
B. अपरिमेय / Irrational
Step 1
Concept
\(\sqrt{11}\) is irrational and (-3) is a non-zero rational multiplier. So the result is irrational.
Step 2
Why this answer is correct
The correct answer is B. अपरिमेय / Irrational. \(\sqrt{11}\) is irrational and (-3) is a non-zero rational multiplier. So the result is irrational.
Step 3
Exam Tip
\(\sqrt{11}\) अपरिमेय है और (-3) शून्येतर परिमेय गुणक है। इसलिए परिणाम अपरिमेय है।
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\(\sqrt{13}\) का विपरीत संख्या कौन-सी है?
What is the additive inverse of \(\sqrt{13}\)?
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A \(\frac{1}{\sqrt{13}}\)
B \(-\sqrt{13}\)
C (13)
D (-13)
Explanation opens after your attempt
Correct Answer
B. \(-\sqrt{13}\)
Step 1
Concept
The additive inverse gives (0) when added, so \(-\sqrt{13}\) is correct. It is also irrational.
Step 2
Why this answer is correct
The correct answer is B. \(-\sqrt{13}\). The additive inverse gives (0) when added, so \(-\sqrt{13}\) is correct. It is also irrational.
Step 3
Exam Tip
विपरीत संख्या जोड़ने पर (0) देती है, इसलिए \(-\sqrt{13}\) सही है। यह भी अपरिमेय है।
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\(\sqrt{13}\) का व्युत्क्रम कौन-सा है?
Which is the reciprocal of \(\sqrt{13}\)?
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A \(-\sqrt{13}\)
B \(\frac{1}{\sqrt{13}}\)
C (13)
D \(\sqrt{13}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{1}{\sqrt{13}}\)
Step 1
Concept
The reciprocal is the number whose product gives (1). \(\sqrt{13}\times\frac{1}{\sqrt{13}}=1\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{1}{\sqrt{13}}\). The reciprocal is the number whose product gives (1). \(\sqrt{13}\times\frac{1}{\sqrt{13}}=1\).
Step 3
Exam Tip
व्युत्क्रम वह है जिसका गुणनफल (1) देता है। \(\sqrt{13}\times\frac{1}{\sqrt{13}}=1\) होता है।
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(\(\sqrt{2}+1\)-\sqrt{2}) का मान क्या है?
What is the value of (\(\sqrt{2}+1\)-\sqrt{2})?
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A अपरिमेय \(\sqrt{2}\) / Irrational \(\sqrt{2}\)
B परिमेय (1) / Rational (1)
C परिमेय (2) / Rational (2)
D अपरिमेय \(1+\sqrt{2}\) / Irrational \(1+\sqrt{2}\)
Explanation opens after your attempt
Correct Answer
B. परिमेय (1) / Rational (1)
Step 1
Concept
The \(\sqrt{2}\) terms cancel and the value is (1). Sometimes irrational terms can cancel to give a rational result.
Step 2
Why this answer is correct
The correct answer is B. परिमेय (1) / Rational (1). The \(\sqrt{2}\) terms cancel and the value is (1). Sometimes irrational terms can cancel to give a rational result.
Step 3
Exam Tip
\(\sqrt{2}\) के पद कट जाते हैं और मान (1) है। कभी-कभी अपरिमेय पद हटकर परिमेय परिणाम दे सकते हैं।
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(\(\sqrt{6}+2\)\(\sqrt{6}-2\)) का मान क्या है?
What is the value of (\(\sqrt{6}+2\)\(\sqrt{6}-2\))?
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A (2)
B \(\sqrt{6}\)
C (10)
D \(4\sqrt{6}\)
Explanation opens after your attempt
Step 1
Concept
This is ((a+b)(a-b)=a-2 -b-2 ), so the value is (6-4=2). Conjugates can make the result rational.
Step 2
Why this answer is correct
The correct answer is A. (2). This is ((a+b)(a-b)=a-2 -b-2 ), so the value is (6-4=2). Conjugates can make the result rational.
Step 3
Exam Tip
यह ((a+b)(a-b)=a-2 -b-2 ) है, इसलिए मान (6-4=2) है। संयुग्मी रूप परिणाम को परिमेय बना सकता है।
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(\(\sqrt{5}+1\)\(\sqrt{5}+1\)) का प्रसार कौन-सा है?
Which is the expansion of (\(\sqrt{5}+1\)\(\sqrt{5}+1\))?
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A \(6+2\sqrt{5}\)
B \(5+\sqrt{5}\)
C (10)
D \(4+2\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
A. \(6+2\sqrt{5}\)
Step 1
Concept
(\(\sqrt{5}+1\)2 =5+2\sqrt{5}+1=6+2\sqrt{5}). Do not forget the middle term.
Step 2
Why this answer is correct
The correct answer is A. \(6+2\sqrt{5}\). (\(\sqrt{5}+1\)2 =5+2\sqrt{5}+1=6+2\sqrt{5}). Do not forget the middle term.
Step 3
Exam Tip
(\(\sqrt{5}+1\)2 =5+2\sqrt{5}+1=6+2\sqrt{5}) है। मध्य पद भूलना नहीं चाहिए।
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\(\sqrt{2}\) और \(\sqrt{3}\) की तुलना में कौन-सा कथन सही है?
Which statement is correct when comparing \(\sqrt{2}\) and \(\sqrt{3}\)?
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A \(\sqrt{2}>\sqrt{3}\)
B \(\sqrt{2}=\sqrt{3}\)
C \(\sqrt{2}<\sqrt{3}\)
D दोनों परिमेय हैं / Both are rational
Explanation opens after your attempt
Correct Answer
C. \(\sqrt{2}<\sqrt{3}\)
Step 1
Concept
Since (2<3), \(\sqrt{2}<\sqrt{3}\). For positive square roots compare the numbers inside.
Step 2
Why this answer is correct
The correct answer is C. \(\sqrt{2}<\sqrt{3}\). Since (2<3), \(\sqrt{2}<\sqrt{3}\). For positive square roots compare the numbers inside.
Step 3
Exam Tip
क्योंकि (2<3), इसलिए \(\sqrt{2}<\sqrt{3}\)। धनात्मक संख्याओं के वर्गमूल में अंदर की संख्या की तुलना करें।
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\(\sqrt{17}\) किन दो पूर्णांकों के बीच है?
Between which two integers does \(\sqrt{17}\) lie?
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A (3) और (4) / (3) and (4)
B (4) और (5) / (4) and (5)
C (5) और (6) / (5) and (6)
D (8) और (9) / (8) and (9)
Explanation opens after your attempt
Correct Answer
B. (4) और (5) / (4) and (5)
Step 1
Concept
Since (16<17<25), \(4<\sqrt{17}<5\). Use nearby perfect squares to decide bounds.
Step 2
Why this answer is correct
The correct answer is B. (4) और (5) / (4) and (5). Since (16<17<25), \(4<\sqrt{17}<5\). Use nearby perfect squares to decide bounds.
Step 3
Exam Tip
क्योंकि (16<17<25), इसलिए \(4<\sqrt{17}<5\)। निकट पूर्ण वर्गों से सीमा तय करें।
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संख्या रेखा पर \(\sqrt{2}\) को किस त्रिभुज से बनाया जा सकता है?
On the number line, \(\sqrt{2}\) can be constructed using which triangle?
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A समकोण त्रिभुज जिसकी भुजाएँ (1) और (1) हों / Right triangle with legs (1) and (1)
B समबाहु त्रिभुज जिसकी भुजा (2) हो / Equilateral triangle with side (2)
C त्रिभुज जिसकी भुजाएँ (2) और (2) हों / Triangle with sides (2) and (2)
D रेखा खंड जिसकी लंबाई (3) हो / Line segment of length (3)
Explanation opens after your attempt
Correct Answer
A. समकोण त्रिभुज जिसकी भुजाएँ (1) और (1) हों / Right triangle with legs (1) and (1)
Step 1
Concept
In a right triangle, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Understand construction using Pythagoras theorem.
Step 2
Why this answer is correct
The correct answer is A. समकोण त्रिभुज जिसकी भुजाएँ (1) और (1) हों / Right triangle with legs (1) and (1). In a right triangle, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Understand construction using Pythagoras theorem.
Step 3
Exam Tip
समकोण त्रिभुज में कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पाइथागोरस प्रमेय से निर्माण समझें।
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किस संख्या को संख्या रेखा पर ठीक-ठीक दिखाया जा सकता है?
Which number can be represented exactly on the number line?
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A केवल परिमेय संख्या / Only rational number
B केवल पूर्णांक / Only integers
C परिमेय और अपरिमेय दोनों / Both rational and irrational numbers
D केवल प्राकृतिक संख्या / Only natural numbers
Explanation opens after your attempt
Correct Answer
C. परिमेय और अपरिमेय दोनों / Both rational and irrational numbers
Step 1
Concept
The number line represents real numbers, including both rational and irrational numbers. Irrationals can be constructed geometrically.
Step 2
Why this answer is correct
The correct answer is C. परिमेय और अपरिमेय दोनों / Both rational and irrational numbers. The number line represents real numbers, including both rational and irrational numbers. Irrationals can be constructed geometrically.
Step 3
Exam Tip
संख्या रेखा पर वास्तविक संख्याएँ दिखाई जाती हैं जिनमें परिमेय और अपरिमेय दोनों शामिल हैं। अपरिमेयों का निर्माण ज्यामिति से किया जा सकता है।
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यदि एक वर्ग की भुजा \(\sqrt{3}\) इकाई है तो उसका क्षेत्रफल क्या होगा?
If the side of a square is \(\sqrt{3}\) units, what will be its area?
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A (3) वर्ग इकाई / (3) square units
B \(\sqrt{3}\) वर्ग इकाई / \(\sqrt{3}\) square units
C (6) वर्ग इकाई / (6) square units
D (9) वर्ग इकाई / (9) square units
Explanation opens after your attempt
Correct Answer
A. (3) वर्ग इकाई / (3) square units
Step 1
Concept
The area is (\(\sqrt{3}\)2 =3). A square with irrational side can have rational area.
Step 2
Why this answer is correct
The correct answer is A. (3) वर्ग इकाई / (3) square units. The area is (\(\sqrt{3}\)2 =3). A square with irrational side can have rational area.
Step 3
Exam Tip
क्षेत्रफल (\(\sqrt{3}\)2 =3) है। अपरिमेय भुजा का क्षेत्रफल परिमेय हो सकता है।
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किस संख्या का वर्ग (19) है और वह धनात्मक है?
Which number has square (19) and is positive?
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A \(\sqrt{19}\)
B (19)
C (361)
D \(-\sqrt{19}\)
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{19}\)
Step 1
Concept
The positive number is \(\sqrt{19}\) because (\(\sqrt{19}\)2 =19). Since (19) is not a perfect square, it is irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{19}\). The positive number is \(\sqrt{19}\) because (\(\sqrt{19}\)2 =19). Since (19) is not a perfect square, it is irrational.
Step 3
Exam Tip
धनात्मक संख्या \(\sqrt{19}\) है क्योंकि (\(\sqrt{19}\)2 =19)। (19) पूर्ण वर्ग नहीं है इसलिए यह अपरिमेय है।
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\(\sqrt{2}\) का दशमलव प्रसार कैसा होता है?
What is the decimal expansion of \(\sqrt{2}\)?
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A सांत / Terminating
B आवर्ती / Repeating
C असांत अनावर्ती / Non-terminating non-repeating
D पूर्णांक / Integer
Explanation opens after your attempt
Correct Answer
C. असांत अनावर्ती / Non-terminating non-repeating
Step 1
Concept
\(\sqrt{2}\) is irrational so its decimal is non-terminating and non-repeating. Do not conclude from only a few decimal digits.
Step 2
Why this answer is correct
The correct answer is C. असांत अनावर्ती / Non-terminating non-repeating. \(\sqrt{2}\) is irrational so its decimal is non-terminating and non-repeating. Do not conclude from only a few decimal digits.
Step 3
Exam Tip
\(\sqrt{2}\) अपरिमेय है इसलिए इसका दशमलव असांत और अनावर्ती होता है। दशमलव के कुछ अंक देखकर निष्कर्ष न लगाएं।
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इनमें से कौन-सा कथन गलत है?
Which of the following statements is false?
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A हर पूर्णांक परिमेय होता है / Every integer is rational
B हर सांत दशमलव परिमेय होता है / Every terminating decimal is rational
C हर अपरिमेय संख्या वास्तविक होती है / Every irrational number is real
D हर वास्तविक संख्या परिमेय होती है / Every real number is rational
Explanation opens after your attempt
Correct Answer
D. हर वास्तविक संख्या परिमेय होती है / Every real number is rational
Step 1
Concept
Every real number is not rational because irrational numbers are also real. The number system includes both types.
Step 2
Why this answer is correct
The correct answer is D. हर वास्तविक संख्या परिमेय होती है / Every real number is rational. Every real number is not rational because irrational numbers are also real. The number system includes both types.
Step 3
Exam Tip
हर वास्तविक संख्या परिमेय नहीं होती क्योंकि अपरिमेय संख्याएँ भी वास्तविक हैं। संख्या तंत्र में दोनों प्रकार शामिल हैं।
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इनमें से कौन-सा युग्म दोनों अपरिमेय संख्याओं का है?
Which pair contains two irrational numbers?
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A \(\sqrt{4}\) और \(\sqrt{9}\) / \(\sqrt{4}\) and \(\sqrt{9}\)
B \(\sqrt{2}\) और \(\sqrt{5}\) / \(\sqrt{2}\) and \(\sqrt{5}\)
C (1 / 2) और \(\sqrt{16}\) / 2) and \(\sqrt{16}\)
D (0.75) और (3) / (0.75) and (3)
Explanation opens after your attempt
Correct Answer
B. \(\sqrt{2}\) और \(\sqrt{5}\) / \(\sqrt{2}\) and \(\sqrt{5}\)
Step 1
Concept
\(\sqrt{2}\) and \(\sqrt{5}\) are both irrational because (2) and (5) are not perfect squares. Check each number separately.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{2}\) और \(\sqrt{5}\) / \(\sqrt{2}\) and \(\sqrt{5}\). \(\sqrt{2}\) and \(\sqrt{5}\) are both irrational because (2) and (5) are not perfect squares. Check each number separately.
Step 3
Exam Tip
\(\sqrt{2}\) और \(\sqrt{5}\) दोनों अपरिमेय हैं क्योंकि (2) और (5) पूर्ण वर्ग नहीं हैं। प्रत्येक संख्या को अलग जाँचें।
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\(\sqrt{28}+\sqrt{63}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{28}+\sqrt{63}\)?
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A \(5\sqrt{7}\)
B \(7\sqrt{5}\)
C \(13\sqrt{7}\)
D \(\sqrt{91}\)
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Correct Answer
A. \(5\sqrt{7}\)
Step 1
Concept
\(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\), so the sum is \(5\sqrt{7}\). Add like radicals.
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{7}\). \(\sqrt{28}=2\sqrt{7}\) and \(\sqrt{63}=3\sqrt{7}\), so the sum is \(5\sqrt{7}\). Add like radicals.
Step 3
Exam Tip
\(\sqrt{28}=2\sqrt{7}\) और \(\sqrt{63}=3\sqrt{7}\), इसलिए योग \(5\sqrt{7}\) है। समान मूलों को जोड़ें।
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\(\sqrt{72}-\sqrt{8}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{72}-\sqrt{8}\)?
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A \(2\sqrt{2}\)
B \(8\sqrt{2}\)
C \(\sqrt{64}\)
D \(4\sqrt{2}\)
Explanation opens after your attempt
Correct Answer
D. \(4\sqrt{2}\)
Step 1
Concept
\(\sqrt{72}=6\sqrt{2}\) and \(\sqrt{8}=2\sqrt{2}\), so the difference is \(4\sqrt{2}\). Simplify like radicals first.
Step 2
Why this answer is correct
The correct answer is D. \(4\sqrt{2}\). \(\sqrt{72}=6\sqrt{2}\) and \(\sqrt{8}=2\sqrt{2}\), so the difference is \(4\sqrt{2}\). Simplify like radicals first.
Step 3
Exam Tip
\(\sqrt{72}=6\sqrt{2}\) और \(\sqrt{8}=2\sqrt{2}\), इसलिए अंतर \(4\sqrt{2}\) है। पहले समान मूलों को सरल करें।
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\(\frac{\sqrt{27}}{3}\) किसके बराबर है?
What is \(\frac{\sqrt{27}}{3}\) equal to?
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A \(3\sqrt{3}\)
B \(\sqrt{3}\)
C (9)
D \(\frac{1}{\sqrt{3}}\)
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Correct Answer
B. \(\sqrt{3}\)
Step 1
Concept
\(\sqrt{27}=3\sqrt{3}\), so \(\frac{\sqrt{27}}{3}=\sqrt{3}\). The result is still irrational.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{3}\). \(\sqrt{27}=3\sqrt{3}\), so \(\frac{\sqrt{27}}{3}=\sqrt{3}\). The result is still irrational.
Step 3
Exam Tip
\(\sqrt{27}=3\sqrt{3}\) है, इसलिए \(\frac{\sqrt{27}}{3}=\sqrt{3}\) होता है। परिणाम अभी भी अपरिमेय है।
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यदि किसी धनात्मक संख्या का वर्ग (37) है, तो वह संख्या कौन-सी होगी?
If the square of a positive number is (37), which number is it?
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A \(\sqrt{37}\)
B (37)
C \(-\sqrt{37}\)
D (74)
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{37}\)
Step 1
Concept
The positive number is \(\sqrt{37}\) because (\(\sqrt{37}\)2 =37). Since (37) is not a perfect square, it is irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{37}\). The positive number is \(\sqrt{37}\) because (\(\sqrt{37}\)2 =37). Since (37) is not a perfect square, it is irrational.
Step 3
Exam Tip
धनात्मक संख्या \(\sqrt{37}\) है क्योंकि (\(\sqrt{37}\)2 =37)। (37) पूर्ण वर्ग नहीं है इसलिए यह अपरिमेय है।
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दशमलव \(3.14114111411114\ldots\) किस प्रकार की संख्या है?
What type of number is the decimal \(3.14114111411114\ldots\)?
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A सांत परिमेय / Terminating rational
B आवर्ती परिमेय / Repeating rational
C अपरिमेय / Irrational
D पूर्णांक / Integer
Explanation opens after your attempt
Correct Answer
C. अपरिमेय / Irrational
Step 1
Concept
This decimal has no fixed repeating block. So it is a non-terminating non-repeating decimal and an irrational number.
Step 2
Why this answer is correct
The correct answer is C. अपरिमेय / Irrational. This decimal has no fixed repeating block. So it is a non-terminating non-repeating decimal and an irrational number.
Step 3
Exam Tip
इस दशमलव में निश्चित दोहराने वाला खंड नहीं है। इसलिए यह असांत अनावर्ती दशमलव और अपरिमेय संख्या है।
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\(\sqrt{96}\) को सरल करने पर कौन-सा रूप मिलता है?
Which form is obtained after simplifying \(\sqrt{96}\)?
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A \(4\sqrt{6}\)
B \(6\sqrt{4}\)
C \(8\sqrt{3}\)
D \(16\sqrt{6}\)
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Correct Answer
A. \(4\sqrt{6}\)
Step 1
Concept
\(\sqrt{96}=\sqrt{16\times6}=4\sqrt{6}\). Since \(\sqrt{6}\) remains, it is irrational.
Step 2
Why this answer is correct
The correct answer is A. \(4\sqrt{6}\). \(\sqrt{96}=\sqrt{16\times6}=4\sqrt{6}\). Since \(\sqrt{6}\) remains, it is irrational.
Step 3
Exam Tip
\(\sqrt{96}=\sqrt{16\times6}=4\sqrt{6}\) है। \(\sqrt{6}\) बचने से यह अपरिमेय है।
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\(\sqrt{44}+\sqrt{99}\) का सरल रूप कौन-सा है?
Which is the simplified form of \(\sqrt{44}+\sqrt{99}\)?
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A \(5\sqrt{11}\)
B \(7\sqrt{11}\)
C \(11\sqrt{13}\)
D \(\sqrt{143}\)
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Correct Answer
A. \(5\sqrt{11}\)
Step 1
Concept
\(\sqrt{44}=2\sqrt{11}\) and \(\sqrt{99}=3\sqrt{11}\), so the sum is \(5\sqrt{11}\). Simplify before adding like radicals.
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{11}\). \(\sqrt{44}=2\sqrt{11}\) and \(\sqrt{99}=3\sqrt{11}\), so the sum is \(5\sqrt{11}\). Simplify before adding like radicals.
Step 3
Exam Tip
\(\sqrt{44}=2\sqrt{11}\) और \(\sqrt{99}=3\sqrt{11}\), इसलिए योग \(5\sqrt{11}\) है। समान मूलों को जोड़ने से पहले सरल करें।
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