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In Class 12 Mathematics, under the chapter Relations and Functions, Introduction to Relations explains a relation as a subset of a Cartesian product. Students learn to form and count relations on sets, and identify important examples such as empty, universal and identity relations. The topic also introduces conditions used to recognise reflexive and symmetric relations.
TOPIC PRACTICE
Quiz this set
Up to 20 questions from this page. Select your focus, then start.
If (A={1,2}) and (B={x,y,z}), how many pairs are there in (A\times B)?
Correct answer: C
Step 1: The number of pairs in (A\times B) is (n(A)n(B)). Step 2: Here (2\times3=6) pairs are formed. Step 3: For different sets multiply the numbers of elements.
If (A={1,2}) and (B={3,4}), which pair belongs to (B\times A)?
Correct answer: A
Step 1: In (B\times A), the first component comes from (B) and the second from (A). Step 2: In ((3,1)), (3) is from (B) and (1) is from (A). Step 3: Always read the order carefully in Cartesian products.
What is the domain of the relation (R={(1,3),(2,3),(2,4)})?
Correct answer: A
Step 1: The domain is formed from the first components of ordered pairs. Step 2: The first components are (1,2,2), so the domain is ({1,2}). Step 3: Write repeated elements only once in a set.
What is the range of the relation (R={(1,3),(2,3),(2,4)})?
Correct answer: B
Step 1: The range is formed from the second components of ordered pairs. Step 2: The second components are (3,3,4), so the range is ({3,4}). Step 3: Remember the different positions for domain and range.
If (R={(a,2),(b,3),(c,2)}), which element is in the domain?
Correct answer: A
Step 1: The domain contains first components. Step 2: The first components of the relation are (a,b,c), so (b) is in the domain. Step 3: Letters and numbers can both occur but position matters most.
If (R={(a,2),(b,3),(c,2)}), which element is in the range?
Correct answer: C
Step 1: The range contains second components. Step 2: Here the second components are (2,3,2), so (2) belongs to the range. Step 3: To find the range look at the right-side components.
What is the inverse relation of (R={(1,4),(2,5),(3,6)})?
Correct answer: A
Step 1: In an inverse relation the two components of every pair are reversed. Step 2: ((1,4),(2,5),(3,6)) become ((4,1),(5,2),(6,3)). Step 3: While finding inverse do not miss any pair.
Step 1: To get (R), reverse every pair of (R^{-1}). Step 2: ((2,1)) gives ((1,2)) and ((3,2)) gives ((2,3)). Step 3: The inverse of the inverse is the original relation.
If (R=R^{-1}), which property of (R) is indicated?
Correct answer: A
Step 1: (R=R^{-1}) means every pair is present with its reverse. Step 2: This is the main idea of a symmetric relation. Step 3: Symmetry can also be recognized through the inverse relation.
Why is (R={(1,1),(2,2),(3,3),(1,2),(2,1)}) symmetric on (A={1,2,3})?
Correct answer: A
Step 1: Diagonal pairs reverse to themselves. Step 2: The non-diagonal pair ((1,2)) has its reverse ((2,1)) present. Step 3: In symmetry check the reverse of every non-diagonal pair.
If (R={(1,1),(2,2),(3,3)}) on (A={1,2,3}), what relation is it?
Correct answer: A
Step 1: Every element is related to itself. Step 2: There is no pair with different components so it is the identity relation. Step 3: Identify the identity relation through diagonal pairs.
What is a relation equal to (A\times A) called on (A={1,2,3})?
Correct answer: A
Step 1: (A\times A) contains all possible ordered pairs. Step 2: A relation containing all these pairs is called the universal relation. Step 3: When you see the full Cartesian product think of universal relation.
Step 1: The domain is formed from first components. Step 2: An empty relation has no pair so there is no first component. Step 3: The domain and range of an empty relation are both empty.
Step 1: The range is formed from second components. Step 2: An empty relation has no ordered pair so it has no second component. Step 3: In an empty relation both domain and range are empty.
If (A={1,2}), how many subsets of (A\times A) are there?
Correct answer: C
Step 1: (A\times A) has (2^2=4) pairs. Step 2: A set with four elements has (2^4=16) subsets. Step 3: The total number of relations equals the number of subsets.
If (A) has (4) elements, what is the number of total relations on (A)?
Correct answer: C
Step 1: (A\times A) has (4^2=16) pairs. Step 2: Each subset forms a relation so the total number of relations is (2^{16}). Step 3: For total relations on (n) elements use (2^{n^2}).
If (A) has (2) elements and (B) has (4) elements, how many total relations are there from (A) to (B)?
Correct answer: B
Step 1: (A\times B) has (2\times4=8) ordered pairs. Step 2: A relation is a subset of (A\times B), so total relations are (2^8). Step 3: For relations between two sets first count (mn) pairs.
What type of relation is (R={(1,1),(1,2),(2,1),(2,2)}) on (A={1,2})?
Correct answer: A
Step 1: These four pairs are all possible pairs of (A\times A). Step 2: Since all are present, the relation is universal. Step 3: For a small set write the full Cartesian product and compare.
If (R={(1,1),(2,2)}) is given, on which set is it the identity relation?
Correct answer: A
Step 1: An identity relation must have the diagonal pair for every element of the base set. Step 2: ((1,1)) and ((2,2)) are complete only for ({1,2}). Step 3: A property of a relation can change when the base set changes.
Is (R={(1,1),(2,2),(3,3),(1,2),(2,1)}) an equivalence relation on (A={1,2,3})?
Correct answer: A
Step 1: All diagonal pairs are present so it is reflexive. Step 2: ((1,2)) and ((2,1)) are both present and transitivity also holds because the needed ((1,1)) and ((2,2)) are present. Step 3: For equivalence relation check all three properties separately.
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