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In Class 12 Mathematics, under the chapter Relations and Functions, Introduction to Relations explains a relation as a subset of a Cartesian product. Students learn to form and count relations on sets, and identify important examples such as empty, universal and identity relations. The topic also introduces conditions used to recognise reflexive and symmetric relations.
TOPIC PRACTICE
Quiz this set
Up to 20 questions from this page. Select your focus, then start.
If (R={(1,1),(2,2)}) is a relation on the set (A={1,2}), what type of relation is it?
Correct answer: A
Step 1: In a reflexive relation, every element must be related to itself. Step 2: Here both ((1,1)) and ((2,2)) are present. Step 3: In exams, first check all ((a,a)) pairs for reflexivity.
How many ordered pairs are there in the empty relation on (A={1,2,3})?
Correct answer: A
Step 1: An empty relation has no ordered pair. Step 2: The number of elements in the set does not matter for an empty relation. Step 3: Always distinguish empty relation from universal relation in exams.
A set (A) has (4) elements. How many ordered pairs will the universal relation on (A) contain?
Correct answer: D
Step 1: A universal relation contains all ordered pairs of (A\times A). Step 2: If (A) has (4) elements, then (A\times A) has (4^2=16) pairs. Step 3: For a universal relation, remember (n^2).
If (R={(1,2),(2,1)}), what is the main property of this relation?
Correct answer: A
Step 1: In a symmetric relation, if ((a,b)) is present, then ((b,a)) must also be present. Step 2: Here both ((1,2)) and ((2,1)) are present. Step 3: In such questions, immediately look for the reverse pair.
On (A={1,2}), (R={(1,1),(1,2),(2,2)}) is given. Why is this relation reflexive?
Correct answer: A
Step 1: Reflexivity needs every element to be related to itself. Step 2: The set has (1) and (2), and both ((1,1)) and ((2,2)) are given. Step 3: Extra pairs do not destroy reflexivity.
If a relation contains ((3,5)) but does not contain ((5,3)), which type can it definitely not be?
Correct answer: A
Step 1: A symmetric relation must contain the reverse of every pair. Step 2: Here ((3,5)) is present but ((5,3)) is absent, so symmetry fails. Step 3: For symmetry, focus on reverse pairs.
On (A={1,2,3}), what is (R={(1,1),(2,2),(3,3)}) called?
Correct answer: A
Step 1: An identity relation contains only pairs of the form ((a,a)). Step 2: Here every element is related only to itself. Step 3: An identity relation is always reflexive.
If (A={a,b}), how many ordered pairs are there in (A\times A)?
Correct answer: C
Step 1: In (A\times A), each element can appear in the first and second positions. Step 2: For (2) elements, the total pairs are (2^2=4). Step 3: Before counting relations, first count (A\times A) correctly.
A relation from two sets (A) and (B) is a subset of what?
Correct answer: A
Step 1: A relation from (A) to (B) is a collection of ordered pairs. Step 2: These pairs are chosen from (A\times B). Step 3: For definition questions, remember that a relation is a subset of the Cartesian product.
If (A) has (3) elements, how many different relations can be formed on (A)?
Correct answer: C
Step 1: A relation on (A) is a subset of (A\times A). Step 2: (A\times A) has (3^2=9) pairs, so the number of subsets is (2^9). Step 3: For total relations, remember (2^{n^2}).
For (R={(1,2),(2,3),(1,3)}) on (A={1,2,3}), which property is visible?
Correct answer: A
Step 1: Transitivity means if ((a,b)) and ((b,c)) are present, then ((a,c)) must also be present. Step 2: Here ((1,2)) and ((2,3)) are accompanied by ((1,3)). Step 3: In transitivity, always check the required third pair.
If ((1,2)) and ((2,3)) are in a relation but ((1,3)) is not, which property fails?
Correct answer: A
Step 1: A transitive relation must complete the forward chain. Step 2: From ((1,2)) and ((2,3)), the pair ((1,3)) is required, but it is missing. Step 3: In such questions, carefully check chain-like pairs.
On (A={1,2}), (R={(1,1),(2,2),(1,2),(2,1)}) is equal to which relation?
Correct answer: A
Step 1: A universal relation contains all pairs of (A\times A). Step 2: For (A={1,2}), all four possible pairs are given. Step 3: If no possible pair is left out, the relation is universal.
Which condition is necessary for a relation to be reflexive?
Correct answer: A
Step 1: Reflexivity is about being related to oneself. Step 2: So for every element (a), the pair ((a,a)) must be in the relation. Step 3: In definition questions, connect the symbols with their meaning.
Which condition is correct for a relation to be symmetric?
Correct answer: A
Step 1: Symmetry means the reverse ordered pair must also belong to the relation. Step 2: So ((b,a)) must be present whenever ((a,b)) is present. Step 3: Remember symmetry as the reverse-pair rule.
Step 1: Transitivity is the rule of completing a relation chain. Step 2: If ((a,b)) and ((b,c)) are present, then ((a,c)) must be present. Step 3: In transitivity, notice the common middle element.
Option A is correct. Reflexivity requires every element of A to be related to itself, so the three diagonal pairs (1,1), (2,2), and (3,3) must all be present. Option A contains all three, and any additional pair such as (1,2) is allowed. Option B lacks (3,3), option C lacks all diagonal pairs, and option D lacks (2,2); therefore none of them is reflexive on the whole set.
For (R={(1,1),(2,2),(3,3),(1,2),(2,1)}) on (A={1,2,3}), which property is definitely present?
Correct answer: A
Step 1: Reflexivity needs ((1,1)), ((2,2)), and ((3,3)). Step 2: All three pairs are present in the relation. Step 3: Extra pairs do not remove reflexivity.
If relation (R) contains only ((1,2)), is it reflexive on (A={1,2})?
Correct answer: A
Step 1: On (A={1,2}), reflexivity needs ((1,1)) and ((2,2)). Step 2: The relation has only ((1,2)), so the required self-pairs are missing. Step 3: In reflexivity, focus on self-pairs.
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