Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 361-370 of 600 questions.
C. (360)
टीमों की जोड़ियां \(\binom{16}{2}=120\) हैं। हर जोड़ी के (3) मैच होने से कुल (360) मैच होंगे। / The pairs of teams are \(\binom{16}{2}=120\). With (3) matches for each pair the total is (360).
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A. (714)
कुल \(\binom{12}{6}=924\) हैं और दोनों विशेष साथ हों तो \(\binom{10}{4}=210\) हैं। इसलिए (924-210=714) तरीके हैं। / Total ways are \(\binom{12}{6}=924\) and ways with both special persons are \(\binom{10}{4}=210\). Hence (924-210=714).
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C. (13398)
मामले (4), (5) और (6) गणित पुस्तकों के हैं। कुल \(\binom{11}{4}\binom{8}{2}+\binom{11}{5}\binom{8}{1}+\binom{11}{6}=13398\) है। / The cases are (4), (5), and (6) mathematics books. The total is \(\binom{11}{4}\binom{8}{2}+\binom{11}{5}\binom{8}{1}+\binom{11}{6}=13398\).
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C. (23310)
अंग्रेजी पुस्तकों की संख्या (2), (3) या (4) हो सकती है। कुल \(\binom{9}{2}\binom{10}{4}+\binom{9}{3}\binom{10}{3}+\binom{9}{4}\binom{10}{2}=23310\) है। / The number of English books can be (2), (3), or (4). The total is \(\binom{9}{2}\binom{10}{4}+\binom{9}{3}\binom{10}{3}+\binom{9}{4}\binom{10}{2}=23310\).
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B. (8106)
डॉक्टरों की संख्या (4), (5) या (6) होगी। कुल \(\binom{10}{4}\binom{8}{2}+\binom{10}{5}\binom{8}{1}+\binom{10}{6}=8106\) है। / The number of doctors will be (4), (5), or (6). The total is \(\binom{10}{4}\binom{8}{2}+\binom{10}{5}\binom{8}{1}+\binom{10}{6}=8106\).
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In how many ways can at least (4) and at most (6) gifts be selected from (14) different gifts?
C. (6006)
चयन (4), (5) या (6) उपहारों का होगा। कुल \(\binom{14}{4}+\binom{14}{5}+\binom{14}{6}=6006\) है। / The selection can be of (4), (5), or (6) gifts. The total is \(\binom{14}{4}+\binom{14}{5}+\binom{14}{6}=6006\).
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B. (196)
एक रंग तय और एक हट गया है। बाकी (5) रंग (10) में से चुनें और दोनों अन्य रंग न आने वाले \(\binom{8}{5}\) चयन घटाएं तो (196) मिलेगा। / One color is fixed and one is excluded. Choose the remaining (5) colors from (10) and subtract \(\binom{8}{5}\) selections missing both other colors to get (196).
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B. (560)
(5) विशेष में से (3) और बाकी (8) में से (3) चुनेंगे। तरीके \(\binom{5}{3}\binom{8}{3}=560\) हैं। / Choose (3) from (5) special students and (3) from the remaining (8). The ways are \(\binom{5}{3}\binom{8}{3}=560\).
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C. (8800)
कुल \(\binom{16}{7}=11440\) हैं। (0) और (1) विशेष वाले चयन हटाने पर \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\) है। / Total ways are \(\binom{16}{7}=11440\). Removing selections with (0) and (1) special student gives \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\).
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B. (13860)
ठीक (3) पुरुष और (3) महिलाएं चाहिए। तरीके \(\binom{11}{3}\binom{9}{3}=13860\) हैं। / Exactly (3) men and (3) women are needed. The ways are \(\binom{11}{3}\binom{9}{3}=13860\).
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