Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 291-300 of 591 questions.
If \(7x\geq -21\), what is the correct solution?
A. \(x\geq -3\)
धनात्मक (7) से भाग देने पर असमानता की दिशा नहीं बदलती। इसलिए \(x\geq -3\) है। / Dividing by positive (7) does not change the direction of the inequality. Therefore \(x\geq -3\).
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Solve the inequality \(-7x\leq 28\).
A. \(x\geq -4\)
(-7) से भाग देने पर चिन्ह उलटकर \(\geq\) हो जाता है। इसलिए \(x\geq -4\) मिलता है। / Dividing by (-7) reverses the sign to \(\geq\). Therefore \(x\geq -4\) is obtained.
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Which option is the interval form of \({x:x\leq 8}\)?
A. (\(-\infty,8]\)
\(x\leq 8\) में (8) शामिल है और उससे छोटे सभी मान आते हैं। इसलिए (\(-\infty,8]\) सही है। / In \(x\leq 8\), (8) is included and all smaller values are taken. Hence (\(-\infty,8]\) is correct.
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If \(0<x\leq 4\), which of the following is a solution?
A. (x=4)
(0) शामिल नहीं है लेकिन (4) शामिल है। इसलिए दिए गए विकल्पों में (x=4) सही है। / (0) is not included, but (4) is included. Therefore (x=4) is correct among the given options.
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What is the solution of \(6-\frac{x}{3}\geq 2\)?
A. \(x\leq 12\)
\(-\frac{x}{3}\geq -4\) से ऋणात्मक गुणक हटाने पर \(x\leq 12\) मिलता है। चिन्ह बदलने की स्थिति पहचानें। / \(-\frac{x}{3}\geq -4\), and removing the negative factor gives \(x\leq 12\). Identify when the sign must be reversed.
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A number increased by (8) is less than (15). What is the correct inequality?
A. (x+8<15)
संख्या में (8) जोड़ना (x+8) है और से कम का अर्थ (<) होता है। शब्द प्रश्नों में मुख्य क्रिया पहचानें। / Increasing a number by (8) is (x+8), and less than means (<). Identify the main operation in word problems.
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Which statement explains the difference between (x>9) and \(x\geq 9\)?
A. \(x\geq 9\) में (9) शामिल है\(x\geq 9\) includes (9)
(>) सीमा को शामिल नहीं करता लेकिन \(\geq\) सीमा को शामिल करता है। इसी से खुला या बंद वृत्त तय होता है। / (>) does not include the boundary, but \(\geq\) includes it. This decides the open or closed circle.
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What is the solution of \(5\leq x+2<11\)?
A. \(3\leq x<9\)
सभी भागों से (2) घटाने पर \(3\leq x<9\) मिलता है। संयुक्त असमानता में हर भाग पर समान क्रिया करें। / Subtracting (2) from all parts gives \(3\leq x<9\). Apply the same operation to every part of a compound inequality.
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Which option represents \(x\in\mathbb{R}\) and (x<0)?
A. (\(-\infty,0\))
(x<0) में सभी ऋणात्मक वास्तविक संख्याएं आती हैं और (0) शामिल नहीं होता। इसलिए (\(-\infty,0\)) सही है।
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A. \(m\leq 5\)
खर्च की असमानता \(150+80m\leq 550\) होगी, जिससे \(m\leq 5\) मिलता है। अधिक नहीं का अर्थ \(\leq\) याद रखें। / The cost inequality is \(150+80m\leq 550\), which gives \(m\leq 5\). Remember that not exceed means \(\leq\).
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