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Which statement shows that the proof of irrationality of (\sqrt{2}) is not based on decimals?

Answer and explanation

Correct answer: The proof is based on rational assumption and contradiction of coprimality

Step 1: A decimal approximation of (\sqrt{2}) does not prove irrationality. Step 2: The real proof assumes (\sqrt{2}=\frac{p}{q}) and derives a contradiction. Step 3: In exams, give priority to logical proof.

Related tags

Real-NumbersRoot2Decimal-Vs-ProofIrrationalityProof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

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