Which statement is correct for (\sqrt{2}) but not directly correct for the usual proof of (\sqrt{3})?
Answer and explanation
Correct answer: Numerator and denominator both become even
Step 1: For (\sqrt{2}), the common factor is (2), so numerator and denominator become even. Step 2: For (\sqrt{3}), the common factor is (3), so evenness is not the direct point. Step 3: Identify the related prime for each root.
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What is the correct answer to this question?
Numerator and denominator both become even
Why is this the correct answer?
Step 1: For (\sqrt{2}), the common factor is (2), so numerator and denominator become even. Step 2: For (\sqrt{3}), the common factor is (3), so evenness is not the direct point. Step 3: Identify the related prime for each root.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
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