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Which option states the final contradiction in the proof of (\sqrt{2}) most correctly?

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Answer and explanation

Correct answer: (a) and (b) were assumed coprime, but both turned out even

Step 1: In lowest form, (a) and (b) were assumed coprime. Step 2: The proof shows both are even, so both have common factor (2). Step 3: This is the correct final contradiction.

Related tags

Sqrt2 ProofFinal ContradictionHardClass 10

Frequently asked questions

What is the correct answer to this question?

(a) and (b) were assumed coprime, but both turned out even

Why is this the correct answer?

Step 1: In lowest form, (a) and (b) were assumed coprime. Step 2: The proof shows both are even, so both have common factor (2). Step 3: This is the correct final contradiction.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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