Which option states the final contradiction in the proof of (\sqrt{2}) most correctly?
Answer and explanation
Correct answer: (a) and (b) were assumed coprime, but both turned out even
Step 1: In lowest form, (a) and (b) were assumed coprime. Step 2: The proof shows both are even, so both have common factor (2). Step 3: This is the correct final contradiction.
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What is the correct answer to this question?
(a) and (b) were assumed coprime, but both turned out even
Why is this the correct answer?
Step 1: In lowest form, (a) and (b) were assumed coprime. Step 2: The proof shows both are even, so both have common factor (2). Step 3: This is the correct final contradiction.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
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