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Which option states the final contradiction in the proof of (\sqrt{2}) in correct language?

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Answer and explanation

Correct answer: (p) and (q) were assumed coprime, but both turned out divisible by (2)

Step 1: At the start, (\frac{p}{q}) is taken in lowest form, so (p) and (q) are assumed coprime. Step 2: The proof shows both are divisible by (2). Step 3: This is the clear and correct contradiction.

Related tags

Sqrt2 ProofFinal ContradictionHardClass 10

Frequently asked questions

What is the correct answer to this question?

(p) and (q) were assumed coprime, but both turned out divisible by (2)

Why is this the correct answer?

Step 1: At the start, (\frac{p}{q}) is taken in lowest form, so (p) and (q) are assumed coprime. Step 2: The proof shows both are divisible by (2). Step 3: This is the clear and correct contradiction.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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