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Which option shows an incorrect argument in the proof of irrationality of (\sqrt{2})?
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Answer and explanation
Correct answer: (p^2) is even, so (p) is odd
Step 1: If (p^2) is even, then (p) is even. Step 2: Calling (p) odd violates the parity rule. Step 3: In error-based questions, check small rules carefully.
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What is the correct answer to this question?
(p^2) is even, so (p) is odd
Why is this the correct answer?
Step 1: If (p^2) is even, then (p) is even. Step 2: Calling (p) odd violates the parity rule. Step 3: In error-based questions, check small rules carefully.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
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