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Class 10MathematicsReal NumbersProof of irrationality of √2, √3, √5MediumLevel 17

Which option is the correct short proof idea for the irrationality of (\sqrt{3})?

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Answer and explanation

Correct answer: Assuming rational makes both numerator and denominator divisible by (3)

Step 1: Assume (\sqrt{3}) rational and write it in lowest form. Step 2: The proof shows both numerator and denominator divisible by (3). Step 3: This contradicts the condition of a lowest-form fraction.

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sqrt3 proofshort proofclass 10

Frequently asked questions

What is the correct answer to this question?

Assuming rational makes both numerator and denominator divisible by (3)

Why is this the correct answer?

Step 1: Assume (\sqrt{3}) rational and write it in lowest form. Step 2: The proof shows both numerator and denominator divisible by (3). Step 3: This contradicts the condition of a lowest-form fraction.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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