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What is the nature of the roots of the equation \(x^2+x+3=0\)?

Answer and explanation

Correct answer: no real roots

Here, \(a=1\), \(b=1\), and \(c=3\). The discriminant is \(D=b^2-4ac=1^2-4(1)(3)=-11\). Since \(D<0\), the equation has no real roots; its roots are complex. Exam tip: \(D<0\) means no real roots, whereas \(D=0\) gives two equal real roots.

Related tags

Quadratic EquationsNature Of RootsDiscriminantNo Real RootsMathematicsClass 10 Mcq

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