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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHard
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What is the smallest number that leaves remainder (5) when divided by (18), (24), and (30)?

Answer and explanation

Correct answer: (365)

Step 1: If the remainder is (5), then subtracting (5) makes the number divisible by (18), (24), and (30). Step 2: Their LCM is (360), so the smallest number is (360+5=365). Step 3: For common remainder questions, subtract the remainder first.

Related tags

Real-NumbersLcmRemainderHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq
सुधार सुझाएँ / Earn

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10 more MCQs
  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
  2. 2What is the HCF of (18) and (24) using prime factorisation?
  3. 3What is the LCM of (18) and (24) using prime factorisation?
  4. 4What is the HCF of (40) and (60)?
  5. 5What is the LCM of (40) and (60)?
  6. 6What will be the HCF of (45) and (75)?
  7. 7What will be the LCM of (45) and (75)?
  8. 8Which is the HCF of (32) and (48)?
  9. 9Which is the LCM of (32) and (48)?
  10. 10What is the HCF of (27) and (36)?
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