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What is the nature of the roots of \(x^2-x-1=0\)?

Answer and explanation

Correct answer: Two real, irrational and distinct roots \((D=5)\)

For a quadratic equation \(ax^2+bx+c=0\), the discriminant is \(D=b^2-4ac\). Here, \(a=1,b=-1,c=-1\), so \(D=(-1)^2-4(1)(-1)=5\). Since \(D>0\), the roots are real and distinct; since 5 is not a perfect square, the roots are irrational. Therefore, option A is correct. Exam tip: If \(D>0\) and \(D\) is not a perfect square, the roots are real, distinct, and irrational.

Related tags

Quadratic-EquationsNature-Of-RootsDiscriminantIrrational-RootsClass-10-MathematicsNature Of RootsQuadratic EquationsMathematics

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