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What is the nature of roots of \(x^2+\frac{1}{2}x+\frac{1}{16}=0\)?द्विघात समीकरण \(x^2+\frac{1}{2}x+\frac{1}{16}=0\) के मूलों की प्रकृति क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Two equal real rootsदो बराबर वास्तविक मूल
Here \(D=\left(\frac{1}{2}\right)^2-4\cdot1\cdot\frac{1}{16}=0\), so the roots are equal and real. In exams, square the denominator too while squaring a fraction.यहां \(D=\left(\frac{1}{2}\right)^2-4\cdot1\cdot\frac{1}{16}=0\), इसलिए मूल बराबर वास्तविक हैं। परीक्षा में fraction को square करते समय denominator भी square करें।
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