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What is the nature of roots of (x^2+2(3u+1)x+9u^2-6u+5=0)?समीकरण (x^2+2(3u+1)x+9u^2-6u+5=0) के मूलों की प्रकृति क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Always real and distinctहमेशा वास्तविक और भिन्न
Here (D=4(3u+1)^2-4(9u^2-6u+5)=48u-16). Thus the nature depends on (u), not always distinct.यहाँ (D=4(3u+1)^2-4(9u^2-6u+5)=48u-16) है। अतः प्रकृति (u) पर निर्भर करेगी, हमेशा भिन्न नहीं होगी।
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