समीकरण (x-2-2(c+1)x+c-2-2c+5=0) के वास्तविक मूलों के लिए (c) पर क्या शर्त है?
What condition on (c) is needed for real roots of (x-2-2(c+1)x+c-2-2c+5=0)?
Explanation opens after your attempt
A. \(c\ge1\)
Concept
For real roots, \(D\ge0\) is required. Here (D=16(c-1)), so \(c\ge1\).
Why this answer is correct
The correct answer is A. \(c\ge1\). For real roots, \(D\ge0\) is required. Here (D=16(c-1)), so \(c\ge1\).
Exam Tip
वास्तविक मूलों के लिए \(D\ge0\) चाहिए। यहाँ (D=16(c-1)), इसलिए \(c\ge1\)।
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