\(15x^2+16x+4=0\) के मूल क्या हैं?
What are the roots of \(15x^2+16x+4=0\)?
Explanation opens after your attempt
A. \(x=-\frac{2}{3},-\frac{2}{5}\)
Concept
(15x-2+16x+4=(3x+2)(5x+2)), so the roots are \(-\frac{2}{3}\) and \(-\frac{2}{5}\). In exams, write fractional roots in simplest form.
Why this answer is correct
The correct answer is A. \(x=-\frac{2}{3},-\frac{2}{5}\). (15x-2+16x+4=(3x+2)(5x+2)), so the roots are \(-\frac{2}{3}\) and \(-\frac{2}{5}\). In exams, write fractional roots in simplest form.
Exam Tip
(15x-2+16x+4=(3x+2)(5x+2)), इसलिए मूल \(-\frac{2}{3}\) और \(-\frac{2}{5}\) हैं। परीक्षा में भिन्न मूलों को सरल रूप में लिखें।
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