\(15x^2+16x+4=0\) के मूल क्या हैं?

What are the roots of \(15x^2+16x+4=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=-\frac{2}{3},-\frac{2}{5}\)

Step 1

Concept

(15x-2+16x+4=(3x+2)(5x+2)), so the roots are \(-\frac{2}{3}\) and \(-\frac{2}{5}\). In exams, write fractional roots in simplest form.

Step 2

Why this answer is correct

The correct answer is A. \(x=-\frac{2}{3},-\frac{2}{5}\). (15x-2+16x+4=(3x+2)(5x+2)), so the roots are \(-\frac{2}{3}\) and \(-\frac{2}{5}\). In exams, write fractional roots in simplest form.

Step 3

Exam Tip

(15x-2+16x+4=(3x+2)(5x+2)), इसलिए मूल \(-\frac{2}{3}\) और \(-\frac{2}{5}\) हैं। परीक्षा में भिन्न मूलों को सरल रूप में लिखें।

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Mathematics Answer, Explanation and Revision Hints

\(15x^2+16x+4=0\) के मूल क्या हैं? / What are the roots of \(15x^2+16x+4=0\)?

Correct Answer: A. \(x=-\frac{2}{3},-\frac{2}{5}\). Explanation: (15x-2+16x+4=(3x+2)(5x+2)), इसलिए मूल \(-\frac{2}{3}\) और \(-\frac{2}{5}\) हैं। परीक्षा में भिन्न मूलों को सरल रूप में लिखें। / (15x-2+16x+4=(3x+2)(5x+2)), so the roots are \(-\frac{2}{3}\) and \(-\frac{2}{5}\). In exams, write fractional roots in simplest form.

Which concept should I revise for this Mathematics MCQ?

(15x-2+16x+4=(3x+2)(5x+2)), so the roots are \(-\frac{2}{3}\) and \(-\frac{2}{5}\). In exams, write fractional roots in simplest form.

What exam hint can help solve this Mathematics question?

(15x-2+16x+4=(3x+2)(5x+2)), इसलिए मूल \(-\frac{2}{3}\) और \(-\frac{2}{5}\) हैं। परीक्षा में भिन्न मूलों को सरल रूप में लिखें।