Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

In the proof of (\sqrt{3}), (p^2=3q^2) gives (p=3k) and then (q=3r). Why does this make the original assumption false?

Advertisement

Answer and explanation

Correct answer: Because (\frac{p}{q}) was assumed in lowest form, but common factor (3) was found

Step 1: In the rational assumption, (\frac{p}{q}) was taken in lowest form. Step 2: (p=3k) and (q=3r) show common factor (3) in both. Step 3: This contradicts lowest form, so the rational assumption is false.

Related tags

Sqrt3 ProofRational AssumptionContradictionHard

Frequently asked questions

What is the correct answer to this question?

Because (\frac{p}{q}) was assumed in lowest form, but common factor (3) was found

Why is this the correct answer?

Step 1: In the rational assumption, (\frac{p}{q}) was taken in lowest form. Step 2: (p=3k) and (q=3r) show common factor (3) in both. Step 3: This contradicts lowest form, so the rational assumption is false.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement