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In the proof of (\sqrt{3}), if both (a) and (b) are found divisible by (3), which condition is broken?

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Answer and explanation

Correct answer: The condition of being coprime

Step 1: Coprime numbers have no common factor except (1). Step 2: If both (a) and (b) are divisible by (3), they have common factor (3). Step 3: This is the contradiction in the proof.

Related tags

Sqrt3 ProofCoprimeContradictionClass 10

Frequently asked questions

What is the correct answer to this question?

The condition of being coprime

Why is this the correct answer?

Step 1: Coprime numbers have no common factor except (1). Step 2: If both (a) and (b) are divisible by (3), they have common factor (3). Step 3: This is the contradiction in the proof.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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