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In the proof of (\sqrt{2}), if (q^2=2k^2) is obtained, what conclusion follows about (q)?
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Answer and explanation
Correct answer: (q) is even
Step 1: From (q^2=2k^2), (q^2) is divisible by (2). Step 2: If the square of an integer is even, the integer is also even. Step 3: So (q) is even, which helps form the contradiction.
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What is the correct answer to this question?
(q) is even
Why is this the correct answer?
Step 1: From (q^2=2k^2), (q^2) is divisible by (2). Step 2: If the square of an integer is even, the integer is also even. Step 3: So (q) is even, which helps form the contradiction.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.
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