Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

In the proof of (\sqrt{2}), if (a=2m) and (b=2n), what does this go against?

Answer and explanation

Correct answer: (\gcd(a,b)=1)

Step 1: (a=2m) and (b=2n) show common factor (2) in both. Step 2: So (\gcd(a,b)) cannot be (1). Step 3: This goes against the lowest-form condition.

Related tags

Sqrt2 ProofGcd ContradictionHardClass 10Proof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Add Muft Shiksha to your Home Screen

In Safari, tap Share, then Add to Home Screen.