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In the proof of (\sqrt{2}), after (p) is found even, what type of number is (k) in (p=2k)?

Answer and explanation

Correct answer: Integer

Step 1: An even integer is written as (2) times an integer. Step 2: Therefore in (p=2k), (k) is an integer. Step 3: Mentioning the type of (k) makes the proof clear.

Related tags

IntegerEven FormSqrt2Class 10Proof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

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