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In the proof for (\sqrt{5}), both (a) and (b) being divisible by (5) breaks which initial condition?(\sqrt{5}) के प्रमाण में (a) और (b) दोनों (5) से विभाज्य होना किस प्रारंभिक शर्त को तोड़ता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Both are coprimeदोनों सहअभाज्य हैं
Step 1: At the beginning, (\frac{a}{b}) was taken in lowest form. Step 2: This means (a) and (b) are coprime. Step 3: (5) being common to both breaks this condition.चरण 1: शुरुआत में (\frac{a}{b}) को सरलतम रूप में लिया गया था। चरण 2: इसका अर्थ है कि (a) और (b) सहअभाज्य हैं। चरण 3: दोनों में (5) साझा होना इसी शर्त को तोड़ता है।
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