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Class 10MathematicsQuadratic EquationsNature of RootsHard
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If (x^2-2(k+3)x+(k^2+6k+5)=0), what will be the nature of its roots?

Answer and explanation

Correct answer: Two distinct real roots for all real (k)

Here (D=[-2(k+3)]^2-4(k^2+6k+5)=16), so (D>0). In exams, the sign of (D) after simplification gives the final answer.

Related tags

Quadratic EquationsNature Of RootsParameter DiscriminantNature Of RootsQuadratic EquationsMathematicsClass 10 Mcq
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