यदि \(x^2+px+q=0\) की जड़ें (-3) और (7) हैं, तो (p-q) का मान क्या है?
If the roots of \(x^2+px+q=0\) are (-3) and (7), what is the value of (p-q)?
Explanation opens after your attempt
C. (17)
Concept
The sum of roots is (4), so (p=-4). The product is (-21), so (q=-21), hence (p-q=17).
Why this answer is correct
The correct answer is C. (17). The sum of roots is (4), so (p=-4). The product is (-21), so (q=-21), hence (p-q=17).
Exam Tip
जड़ों का योग (4) है, इसलिए (p=-4)। गुणनफल (-21) है, इसलिए (q=-21), अतः (p-q=17)।
Login to save your score, XP, coins and progress.
