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If the two roots of the equation \(2x^2+nx+8=0\) are equal, what is the value of \(n^2\)?
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Answer and explanation
Correct answer: 64
For equal roots, the discriminant \(D=b^2-4ac\) must be zero. Here, \(a=2\), \(b=n\), and \(c=8\), so \(n^2-4(2)(8)=0\), giving \(n^2=64\). Remember that the question asks for \(n^2\), not \(n\).
Frequently asked questions
What is the correct answer to this question?
64
Why is this the correct answer?
For equal roots, the discriminant \(D=b^2-4ac\) must be zero. Here, \(a=2\), \(b=n\), and \(c=8\), so \(n^2-4(2)(8)=0\), giving \(n^2=64\). Remember that the question asks for \(n^2\), not \(n\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Nature of Roots.
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