यदि \(t=\sqrt{13}+\sqrt{12}\), तो (t\cdot\(\sqrt{13}-\sqrt{12}\)) का मान क्या है?
If \(t=\sqrt{13}+\sqrt{12}\), what is the value of (t\cdot\(\sqrt{13}-\sqrt{12}\))?
Explanation opens after your attempt
Correct Answer
A. (1)
Concept
(\(\sqrt{13}+\sqrt{12}\)\(\sqrt{13}-\sqrt{12}\)=13-12=1). In exams, the product of conjugate surds is rational.
Why this answer is correct
The correct answer is A. (1). (\(\sqrt{13}+\sqrt{12}\)\(\sqrt{13}-\sqrt{12}\)=13-12=1). In exams, the product of conjugate surds is rational.
Exam Tip
(\(\sqrt{13}+\sqrt{12}\)\(\sqrt{13}-\sqrt{12}\)=13-12=1)। परीक्षा में करणी वाले संयुग्म का गुणनफल परिमेय होता है।
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