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If (\sqrt{5}=\frac{p}{q}) is assumed in lowest form and (p=5k) is obtained in the proof, what is the next important aim?

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Answer and explanation

Correct answer: To show that (q) is also divisible by (5)

Step 1: (p=5k) shows that (p) is divisible by (5). Step 2: Substituting it in (p^2=5q^2) gives (q^2=5k^2), so (q) is also divisible by (5). Step 3: A common factor (5) in both creates the contradiction.

Related tags

Sqrt5 ProofCommon FactorContradictionHard

Frequently asked questions

What is the correct answer to this question?

To show that (q) is also divisible by (5)

Why is this the correct answer?

Step 1: (p=5k) shows that (p) is divisible by (5). Step 2: Substituting it in (p^2=5q^2) gives (q^2=5k^2), so (q) is also divisible by (5). Step 3: A common factor (5) in both creates the contradiction.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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