यदि (p(x)=x-2+ax+6) का एक शून्यक \(-\sqrt{6}\) है और दूसरा \(\sqrt{6}\) है, तो (a) क्या है?
If one zero of (p(x)=x-2+ax+6) is \(-\sqrt{6}\) and the other is \(\sqrt{6}\), what is (a)?
Explanation opens after your attempt
Correct Answer
A. (0)
Concept
The sum of the zeroes is (0), and in \(x^2+ax+6\), the sum is (-a). Thus (a=0).
Why this answer is correct
The correct answer is A. (0). The sum of the zeroes is (0), and in \(x^2+ax+6\), the sum is (-a). Thus (a=0).
Exam Tip
शून्यकों का योग (0) है और \(x^2+ax+6\) में योग (-a) होता है। अतः (a=0)।
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