If assuming (\sqrt{n}=\frac{p}{q}) and squaring gives (p^2=nq^2), which proof begins when (n=5)?

Question

Answer and explanation

Correct answer: Proof of irrationality of (\sqrt{5})

Step 1: Putting (n=5) gives the number (\sqrt{5}). Step 2: Squaring gives (p^2=5q^2). Step 3: This starts the irrationality proof of (\sqrt{5}).

What is the correct answer to this question?

Proof of irrationality of (\sqrt{5})

Why is this the correct answer?

Step 1: Putting (n=5) gives the number (\sqrt{5}). Step 2: Squaring gives (p^2=5q^2). Step 3: This starts the irrationality proof of (\sqrt{5}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.