यदि \(x^2-7x+12=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\frac{\alpha+1}{\alpha-1}+\frac{\beta+1}{\beta-1}\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(x^2-7x+12=0\), what is \(\frac{\alpha+1}{\alpha-1}+\frac{\beta+1}{\beta-1}\)?

Explanation opens after your attempt
Correct Answer

C. \(\frac{11}{3}\)

Step 1

Concept

The roots are (3) and (4). Direct substitution gives \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{11}{3}\). The roots are (3) and (4). Direct substitution gives \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\).

Step 3

Exam Tip

जड़ें (3) और (4) हैं। सीधे रखने पर \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-7x+12=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\frac{\alpha+1}{\alpha-1}+\frac{\beta+1}{\beta-1}\) का मान क्या है? / If \(\alpha,\beta\) are the roots of \(x^2-7x+12=0\), what is \(\frac{\alpha+1}{\alpha-1}+\frac{\beta+1}{\beta-1}\)?

Correct Answer: C. \(\frac{11}{3}\). Explanation: जड़ें (3) और (4) हैं। सीधे रखने पर \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\) मिलता है। / The roots are (3) and (4). Direct substitution gives \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\).

Which concept should I revise for this Mathematics MCQ?

The roots are (3) and (4). Direct substitution gives \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\).

What exam hint can help solve this Mathematics question?

जड़ें (3) और (4) हैं। सीधे रखने पर \(\frac{4}{2}+\frac{5}{3}=\frac{11}{3}\) मिलता है।