यदि \(x^2+6x+8=0\) की जड़ें \(\alpha,\beta\) हैं, तो (\(\alpha-\beta\)2+2\alpha\beta) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2+6x+8=0\), what is (\(\alpha-\beta\)2+2\alpha\beta)?

Explanation opens after your attempt
Correct Answer

A. (20)

Step 1

Concept

Here (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4). Then (4+2(8)=20).

Step 2

Why this answer is correct

The correct answer is A. (20). Here (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4). Then (4+2(8)=20).

Step 3

Exam Tip

(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4) है। फिर (4+2(8)=20) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+6x+8=0\) की जड़ें \(\alpha,\beta\) हैं, तो (\(\alpha-\beta\)2+2\alpha\beta) का मान क्या है? / If \(\alpha,\beta\) are roots of \(x^2+6x+8=0\), what is (\(\alpha-\beta\)2+2\alpha\beta)?

Correct Answer: A. (20). Explanation: (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4) है। फिर (4+2(8)=20) मिलता है। / Here (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4). Then (4+2(8)=20).

Which concept should I revise for this Mathematics MCQ?

Here (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4). Then (4+2(8)=20).

What exam hint can help solve this Mathematics question?

(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4) है। फिर (4+2(8)=20) मिलता है।