यदि \(x^2+6x+8=0\) की जड़ें \(\alpha,\beta\) हैं, तो (\(\alpha-\beta\)2+2\alpha\beta) का मान क्या है?
If \(\alpha,\beta\) are roots of \(x^2+6x+8=0\), what is (\(\alpha-\beta\)2+2\alpha\beta)?
Explanation opens after your attempt
A. (20)
Concept
Here (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4). Then (4+2(8)=20).
Why this answer is correct
The correct answer is A. (20). Here (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4). Then (4+2(8)=20).
Exam Tip
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=36-32=4) है। फिर (4+2(8)=20) मिलता है।
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