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If a student writes (\sqrt{3}\approx1.732) and treats it as proof of irrationality, what is the main weakness?

Answer and explanation

Correct answer: A decimal approximation is not a complete proof

Step 1: (1.732) is only an approximate value, not the full value. Step 2: To prove irrationality, we must assume rationality and show a contradiction with coprimality. Step 3: In exams, write a logical proof, not an approximation.

Related tags

Real-NumbersRoot3Decimal-ApproximationProof-QualityProof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

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