\(a_{16}=152\) और (6d=103), इसलिए \(d=\frac{103}{6}\)। \(a_{40}=152+24\cdot\frac{103}{6}=564\)। / \(a_{16}=152\) and (6d=103), so \(d=\frac{103}{6}\). \(a_{40}=152+24\cdot\frac{103}{6}=564\).
Mathematics Answer, Explanation and Revision Hints
यदि \(a_{10}=49\) और \(a_{16}=3a_{10}+5\) है, तो \(a_{40}\) क्या होगा? / If \(a_{10}=49\) and \(a_{16}=3a_{10}+5\), what is \(a_{40}\)?
Correct Answer: C. (559). Explanation: \(a_{16}=152\) और (6d=103), इसलिए \(d=\frac{103}{6}\)। \(a_{40}=152+24\cdot\frac{103}{6}=564\)। / \(a_{16}=152\) and (6d=103), so \(d=\frac{103}{6}\). \(a_{40}=152+24\cdot\frac{103}{6}=564\).
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