यदि (2) और (3) समीकरण \(ax^2+bx+6=0\) के मूल हैं तो (a) का मान क्या है?

If (2) and (3) are roots of \(ax^2+bx+6=0\), what is the value of (a)?

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Correct Answer

A. (1)

Step 1

Concept

The product of roots is \(\frac{c}{a}\). Here \(2\cdot3=\frac{6}{a}\), so (a=1).

Step 2

Why this answer is correct

The correct answer is A. (1). The product of roots is \(\frac{c}{a}\). Here \(2\cdot3=\frac{6}{a}\), so (a=1).

Step 3

Exam Tip

मूलों का गुणनफल \(\frac{c}{a}\) होता है। यहां \(2\cdot3=\frac{6}{a}\) से (a=1) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (2) और (3) समीकरण \(ax^2+bx+6=0\) के मूल हैं तो (a) का मान क्या है? / If (2) and (3) are roots of \(ax^2+bx+6=0\), what is the value of (a)?

Correct Answer: A. (1). Explanation: मूलों का गुणनफल \(\frac{c}{a}\) होता है। यहां \(2\cdot3=\frac{6}{a}\) से (a=1) मिलता है। / The product of roots is \(\frac{c}{a}\). Here \(2\cdot3=\frac{6}{a}\), so (a=1).

Which concept should I revise for this Mathematics MCQ?

The product of roots is \(\frac{c}{a}\). Here \(2\cdot3=\frac{6}{a}\), so (a=1).

What exam hint can help solve this Mathematics question?

मूलों का गुणनफल \(\frac{c}{a}\) होता है। यहां \(2\cdot3=\frac{6}{a}\) से (a=1) मिलता है।