समीकरण \(x^2-9x+20=0\) के मूल कैसे होंगे?
How will the roots of \(x^2-9x+20=0\) be?
Explanation opens after your attempt
Correct Answer
A. दो वास्तविक परिमेय और असमान ((D=1))Two real rational and distinct ((D=1))
Concept
Here (D=(-9)2-4(1)(20)=1). Since (D=1) is a positive perfect square, the roots are rational and distinct.
Why this answer is correct
The correct answer is A. दो वास्तविक परिमेय और असमान ((D=1)) / Two real rational and distinct ((D=1)). Here (D=(-9)2-4(1)(20)=1). Since (D=1) is a positive perfect square, the roots are rational and distinct.
Exam Tip
यहाँ (D=(-9)2-4(1)(20)=1) है। (D=1) धनात्मक पूर्ण वर्ग है, इसलिए मूल परिमेय और असमान हैं।
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