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What is the nature of the roots of the equation \(3x^2-2x-2=0\)?

Answer and explanation

Correct answer: Two real, irrational, and distinct roots \(D=28\)

For a quadratic equation \(ax^2+bx+c=0\), the discriminant is \(D=b^2-4ac\). Here, \(a=3\), \(b=-2\), and \(c=-2\), so \(D=(-2)^2-4(3)(-2)=28\). Since \(D>0\), the roots are real and distinct; since 28 is not a perfect square, the roots are irrational. Option B is incorrect because the discriminant is 28, not 4. Exam tip: If \(D>0\) and is not a perfect square, the roots are real, distinct, and irrational.

Related tags

Quadratic EquationsDiscriminantNature Of RootsIrrational RootsReal RootsMathematicsClass 10 Mcq

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