For which (m) will (x^2+mx+16=0) have equal roots?किस (m) के लिए (x^2+mx+16=0) के मूल बराबर होंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (m=\pm8)(m=\pm8)
For equal roots, (D=0), so (m^2-64=0) and (m=\pm8). In exams, remember (m^2=a^2) gives (m=\pm a).बराबर मूलों के लिए (D=0), अतः (m^2-64=0) और (m=\pm8)। परीक्षा में (m^2=a^2) से (m=\pm a) लिखना न भूलें।
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.