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Choose the nature of roots of (x^2-2\sqrt{5}x+1=0).समीकरण (x^2-2\sqrt{5}x+1=0) के मूलों की प्रकृति चुनिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Real, irrational and distinctवास्तविक, अपरिमेय और भिन्न
Here (D=(2\sqrt{5})^2-4(1)(1)=16>0). The roots are (\sqrt{5}\pm2), so they are irrational and distinct.यहाँ (D=(2\sqrt{5})^2-4(1)(1)=16>0) है। मूल (\sqrt{5}\pm2) होंगे, इसलिए वे अपरिमेय और भिन्न हैं।
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