A student writes in the proof of (\sqrt{2}) that (p^2) is even so (p) is even. Why is this step correct?

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Answer and explanation

Correct answer: Because the square of an odd number is odd

Step 1: If (p) were odd, then (p^2) would also be odd. Step 2: But (p^2) is even, so (p) cannot be odd. Step 3: Thus (p) must be even.

What is the correct answer to this question?

Because the square of an odd number is odd

Why is this the correct answer?

Step 1: If (p) were odd, then (p^2) would also be odd. Step 2: But (p^2) is even, so (p) cannot be odd. Step 3: Thus (p) must be even.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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