two-radicals se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
5 questions tagged with two-radicals.
What is the domain of (f(x)=\sqrt{x+2}+\sqrt{6-x})?
A. ([-2,6])
दोनों वर्गमूलों के लिए \(x+2\ge 0\) और \(6-x\ge 0\) चाहिए। इसलिए \(x\in[-2,6]\)। / For both square roots, \(x+2\ge 0\) and \(6-x\ge 0\) are required. Hence \(x\in[-2,6]\).
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If (f(x)=\sqrt{x-2}+\sqrt{x-8}), what is the domain?
A. \([8,\infty\))
दोनों मूलों के लिए \(x-2\ge 0\) और \(x-8\ge 0\) चाहिए। कठोर शर्त \(x\ge 8\) है। / Both roots require \(x-2\ge 0\) and \(x-8\ge 0\). The stronger condition is \(x\ge 8\).
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What is the domain of (f(x)=\sqrt{x+3}+\sqrt{5-x})?
A. ([-3,5])
दोनों वर्गमूलों के लिए \(x+3\ge 0\) और \(5-x\ge 0\) साथ-साथ चाहिए। संयुक्त शर्तों का प्रतिच्छेद लें। / Both square roots require \(x+3\ge 0\) and \(5-x\ge 0\) simultaneously. Take the intersection of the conditions.
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What is the domain of (f(x)=\sqrt{x-2}+\sqrt{9-x})?
A. ([2,9])
दोनों शर्तें \(x-2\ge0\) और \(9-x\ge0\) मिलकर \(2\le x\le9\) देती हैं। परीक्षा में दो वर्गमूल हों तो common interval लें। / The two conditions \(x-2\ge0\) and \(9-x\ge0\) together give \(2\le x\le9\). In exams take the common interval for two square roots.
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What is the domain of (f(x)=\sqrt{x-1}+\sqrt{7-x})?
A. ([1,7])
शर्तें \(x-1\ge 0\) और \(7-x\ge 0\) मिलकर \(1\le x\le 7\) देती हैं। परीक्षा में संयुक्त डोमेन के लिए प्रतिच्छेद लें। / The conditions \(x-1\ge 0\) and \(7-x\ge 0\) together give \(1\le x\le 7\). In exams take the intersection for the combined domain.
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