फलन (f(x)=\sqrt{x+2}+\sqrt{6-x}) का प्रांत क्या है?

What is the domain of (f(x)=\sqrt{x+2}+\sqrt{6-x})?

Explanation opens after your attempt
Correct Answer

A. ([-2,6])

Step 1

Concept

For both square roots, \(x+2\ge 0\) and \(6-x\ge 0\) are required. Hence \(x\in[-2,6]\).

Step 2

Why this answer is correct

The correct answer is A. ([-2,6]). For both square roots, \(x+2\ge 0\) and \(6-x\ge 0\) are required. Hence \(x\in[-2,6]\).

Step 3

Exam Tip

दोनों वर्गमूलों के लिए \(x+2\ge 0\) और \(6-x\ge 0\) चाहिए। इसलिए \(x\in[-2,6]\)।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{x+2}+\sqrt{6-x}) का प्रांत क्या है? / What is the domain of (f(x)=\sqrt{x+2}+\sqrt{6-x})?

Correct Answer: A. ([-2,6]). Explanation: दोनों वर्गमूलों के लिए \(x+2\ge 0\) और \(6-x\ge 0\) चाहिए। इसलिए \(x\in[-2,6]\)। / For both square roots, \(x+2\ge 0\) and \(6-x\ge 0\) are required. Hence \(x\in[-2,6]\).

Which concept should I revise for this Mathematics MCQ?

For both square roots, \(x+2\ge 0\) and \(6-x\ge 0\) are required. Hence \(x\in[-2,6]\).

What exam hint can help solve this Mathematics question?

दोनों वर्गमूलों के लिए \(x+2\ge 0\) और \(6-x\ge 0\) चाहिए। इसलिए \(x\in[-2,6]\)।