यदि (P(t)=75+8t) और (Q(t)=219-10t) है तो किस (t) पर (P(t)=Q(t)) होगा?
If (P(t)=75+8t) and (Q(t)=219-10t), at which (t) will (P(t)=Q(t))?
#linear_growth_decay
#equality
#solve_time
A (t=6)
B (t=8)
C (t=10)
D (t=12)
Explanation opens after your attempt
Step 1
Concept
From (75+8t=219-10t), (18t=144). Therefore (t=8) is correct.
Step 2
Why this answer is correct
The correct answer is B. (t=8). From (75+8t=219-10t), (18t=144). Therefore (t=8) is correct.
Step 3
Exam Tip
(75+8t=219-10t) से (18t=144) होता है। इसलिए (t=8) सही है।
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यदि (P(t)=70+5t) और (Q(t)=190-10t) है तो किस (t) पर (P(t)=Q(t)) होगा?
If (P(t)=70+5t) and (Q(t)=190-10t), at which (t) will (P(t)=Q(t))?
#linear_growth_decay
#equality
#solve_time
A (t=6)
B (t=8)
C (t=10)
D (t=12)
Explanation opens after your attempt
Step 1
Concept
From (70+5t=190-10t), (15t=120). Therefore (t=8) is correct.
Step 2
Why this answer is correct
The correct answer is B. (t=8). From (70+5t=190-10t), (15t=120). Therefore (t=8) is correct.
Step 3
Exam Tip
(70+5t=190-10t) से (15t=120) होता है। इसलिए (t=8) सही है।
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यदि (P(t)=52+4t) और (Q(t)=148-8t) है तो किस (t) पर (P(t)=Q(t)) होगा?
If (P(t)=52+4t) and (Q(t)=148-8t), at which (t) will (P(t)=Q(t))?
#linear_growth_decay
#equality
#solve_time
A (t=6)
B (t=8)
C (t=10)
D (t=12)
Explanation opens after your attempt
Step 1
Concept
From (52+4t=148-8t), (12t=96). Therefore (t=8) is correct.
Step 2
Why this answer is correct
The correct answer is B. (t=8). From (52+4t=148-8t), (12t=96). Therefore (t=8) is correct.
Step 3
Exam Tip
(52+4t=148-8t) से (12t=96) होता है। इसलिए (t=8) सही है।
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यदि (P(t)=38+6t) और (Q(t)=122-8t) है तो किस (t) पर (P(t)=Q(t)) होगा?
If (P(t)=38+6t) and (Q(t)=122-8t), at which (t) will (P(t)=Q(t))?
#linear_growth_decay
#equality
#solve_time
A (t=4)
B (t=6)
C (t=8)
D (t=14)
Explanation opens after your attempt
Step 1
Concept
From (38+6t=122-8t), (14t=84). Therefore (t=6) is correct.
Step 2
Why this answer is correct
The correct answer is B. (t=6). From (38+6t=122-8t), (14t=84). Therefore (t=6) is correct.
Step 3
Exam Tip
(38+6t=122-8t) से (14t=84) होता है। इसलिए (t=6) सही है।
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यदि (P(t)=55+5t) और (Q(t)=135-3t) है तो किस (t) पर (P(t)=Q(t)) होगा?
If (P(t)=55+5t) and (Q(t)=135-3t), at which (t) will (P(t)=Q(t))?
#linear_growth_decay
#equality
#solve_time
A (t=8)
B (t=10)
C (t=12)
D (t=16)
Explanation opens after your attempt
Step 1
Concept
From (55+5t=135-3t), (8t=80). Therefore (t=10) is correct.
Step 2
Why this answer is correct
The correct answer is B. (t=10). From (55+5t=135-3t), (8t=80). Therefore (t=10) is correct.
Step 3
Exam Tip
(55+5t=135-3t) से (8t=80) होता है। इसलिए (t=10) सही है।
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यदि (P(t)=40+4t) और (Q(t)=100-6t), तो किस (t) पर (P(t)) पहली बार (Q(t)) के बराबर होगा?
If (P(t)=40+4t) and (Q(t)=100-6t), at what (t) will (P(t)) first equal (Q(t))?
#linear_growth_decay
#equality
#solve_time
A (t=4)
B (t=5)
C (t=6)
D (t=10)
Explanation opens after your attempt
Step 1
Concept
From (40+4t=100-6t), (10t=60). Therefore (t=6) is correct.
Step 2
Why this answer is correct
The correct answer is C. (t=6). From (40+4t=100-6t), (10t=60). Therefore (t=6) is correct.
Step 3
Exam Tip
(40+4t=100-6t) से (10t=60) होता है। इसलिए (t=6) सही है।
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एक गोदाम में सामान (I(d)=300-20d) बचता है। कब सामान (120) बचेगा?
Items left in a warehouse are (I(d)=300-20d). When will (120) items be left?
#linear_decay
#word_problem
#solve_time
A (d=7)
B (d=8)
C (d=9)
D (d=10)
Explanation opens after your attempt
Step 1
Concept
From (300-20d=120), (20d=180) and (d=9). Set the remaining amount equal to the target.
Step 2
Why this answer is correct
The correct answer is C. (d=9). From (300-20d=120), (20d=180) and (d=9). Set the remaining amount equal to the target.
Step 3
Exam Tip
(300-20d=120) से (20d=180) और (d=9) है। बची मात्रा को लक्ष्य के बराबर रखें।
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एक क्लब में सदस्य (M(w)=60+4w) हैं। कितने सप्ताह बाद सदस्य (100) होंगे?
Members in a club are (M(w)=60+4w). After how many weeks will the members be (100)?
#linear_growth
#word_problem
#solve_time
A (w=8)
B (w=9)
C (w=10)
D (w=12)
Explanation opens after your attempt
Step 1
Concept
From (60+4w=100), (4w=40) and (w=10). Form an equation for the target number.
Step 2
Why this answer is correct
The correct answer is C. (w=10). From (60+4w=100), (4w=40) and (w=10). Form an equation for the target number.
Step 3
Exam Tip
(60+4w=100) से (4w=40) और (w=10) है। लक्ष्य संख्या के लिए समीकरण बनाएं।
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यदि (U(t)=150-15t), तो (U(t)=45) कब होगा?
If (U(t)=150-15t), when will (U(t)=45)?
#linear_decay
#solve_time
#target
A (t=5)
B (t=6)
C (t=7)
D (t=9)
Explanation opens after your attempt
Step 1
Concept
From (150-15t=45), (15t=105) and (t=7). Move the subtraction term correctly in decay.
Step 2
Why this answer is correct
The correct answer is C. (t=7). From (150-15t=45), (15t=105) and (t=7). Move the subtraction term correctly in decay.
Step 3
Exam Tip
(150-15t=45) से (15t=105) और (t=7) है। क्षय में घटाव को सही दिशा में ले जाएं।
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यदि (T(t)=54+6t), तो (T(t)=102) कब होगा?
If (T(t)=54+6t), when will (T(t)=102)?
#linear_growth
#solve_time
#target
A (t=6)
B (t=7)
C (t=8)
D (t=9)
Explanation opens after your attempt
Step 1
Concept
From (54+6t=102), (6t=48) and (t=8). Solve the equation for the target value.
Step 2
Why this answer is correct
The correct answer is C. (t=8). From (54+6t=102), (6t=48) and (t=8). Solve the equation for the target value.
Step 3
Exam Tip
(54+6t=102) से (6t=48) और (t=8) है। लक्ष्य मान के लिए समीकरण हल करें।
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बैटरी (B(h)=120-10h) प्रतिशत मॉडल से घटती है। बैटरी (50%) कब होगी?
A battery decreases by the model (B(h)=120-10h) percent. When will the battery be (50%)?
#linear_decay
#solve_time
#battery
A (h=5)
B (h=6)
C (h=7)
D (h=8)
Explanation opens after your attempt
Step 1
Concept
From (120-10h=50), (10h=70) and (h=7). Solve the decreasing model carefully.
Step 2
Why this answer is correct
The correct answer is C. (h=7). From (120-10h=50), (10h=70) and (h=7). Solve the decreasing model carefully.
Step 3
Exam Tip
(120-10h=50) से (10h=70) और (h=7) है। क्षय में घटे हुए मान को सावधानी से हल करें।
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बचत राशि (S(m)=400+60m) रुपये है। राशि (760) रुपये कितने महीनों बाद होगी?
The saving amount is (S(m)=400+60m) rupees. After how many months will the amount be (760) rupees?
#linear_growth
#solve_time
#savings
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
From (400+60m=760), (60m=360) and (m=6). Set the target value equal to the model.
Step 2
Why this answer is correct
The correct answer is C. (6). From (400+60m=760), (60m=360) and (m=6). Set the target value equal to the model.
Step 3
Exam Tip
(400+60m=760) से (60m=360) और (m=6) मिलता है। लक्ष्य मान को मॉडल के बराबर रखें।
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एक गोदाम में सामान (I(d)=250-15d) बचता है। कब सामान (100) बचेगा?
Items left in a warehouse are (I(d)=250-15d). When will (100) items be left?
#linear_decay
#word_problem
#solve_time
A (d=8)
B (d=9)
C (d=10)
D (d=15)
Explanation opens after your attempt
Step 1
Concept
From (250-15d=100), (15d=150) and (d=10). In decay set the remaining amount equal to the target.
Step 2
Why this answer is correct
The correct answer is C. (d=10). From (250-15d=100), (15d=150) and (d=10). In decay set the remaining amount equal to the target.
Step 3
Exam Tip
(250-15d=100) से (15d=150) और (d=10) मिलता है। क्षय में बची मात्रा को लक्ष्य के बराबर रखें।
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एक क्लब में सदस्य (M(w)=45+3w) हैं। कितने सप्ताह बाद सदस्य (72) होंगे?
Members in a club are (M(w)=45+3w). After how many weeks will the members be (72)?
#linear_growth
#word_problem
#solve_time
A (w=7)
B (w=8)
C (w=9)
D (w=12)
Explanation opens after your attempt
Step 1
Concept
From (45+3w=72), (3w=27) and (w=9). Form an equation for the target number.
Step 2
Why this answer is correct
The correct answer is C. (w=9). From (45+3w=72), (3w=27) and (w=9). Form an equation for the target number.
Step 3
Exam Tip
(45+3w=72) से (3w=27) और (w=9) है। लक्ष्य संख्या के लिए समीकरण बनाएं।
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यदि (U(t)=120-10t), तो (U(t)=50) कब होगा?
If (U(t)=120-10t), when will (U(t)=50)?
#linear_decay
#solve_time
#target
A (t=5)
B (t=6)
C (t=7)
D (t=8)
Explanation opens after your attempt
Step 1
Concept
From (120-10t=50), (10t=70) and (t=7). Move the subtraction term correctly in decay.
Step 2
Why this answer is correct
The correct answer is C. (t=7). From (120-10t=50), (10t=70) and (t=7). Move the subtraction term correctly in decay.
Step 3
Exam Tip
(120-10t=50) से (10t=70) और (t=7) मिलता है। क्षय में घटाव को सही दिशा में ले जाएं।
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यदि (T(t)=42+3t), तो (T(t)=72) कब होगा?
If (T(t)=42+3t), when will (T(t)=72)?
#linear_growth
#solve_time
#target
A (t=8)
B (t=9)
C (t=10)
D (t=12)
Explanation opens after your attempt
Step 1
Concept
From (42+3t=72), (3t=30) and (t=10). Solve the equation for the target value.
Step 2
Why this answer is correct
The correct answer is C. (t=10). From (42+3t=72), (3t=30) and (t=10). Solve the equation for the target value.
Step 3
Exam Tip
(42+3t=72) से (3t=30) और (t=10) मिलता है। लक्ष्य मान के लिए समीकरण हल करें।
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एक बैटरी (B(h)=96-6h) प्रतिशत बचती है। बैटरी (48%) कब होगी?
A battery remains (B(h)=96-6h) percent. When will the battery be (48%)?
#linear_decay
#solve_time
#battery
A (6) घंटे / (6) hours
B (7) घंटे / (7) hours
C (8) घंटे / (8) hours
D (9) घंटे / (9) hours
Explanation opens after your attempt
Correct Answer
C. (8) घंटे / (8) hours
Step 1
Concept
From (96-6h=48), (6h=48) and (h=8). In decay set the remaining value equal to the target.
Step 2
Why this answer is correct
The correct answer is C. (8) घंटे / (8) hours. From (96-6h=48), (6h=48) and (h=8). In decay set the remaining value equal to the target.
Step 3
Exam Tip
(96-6h=48) से (6h=48) और (h=8) मिलता है। क्षय में बचा हुआ मान लक्ष्य के बराबर रखें।
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एक बचत राशि (S(m)=300+40m) रुपये है। कितने महीनों बाद राशि (620) रुपये होगी?
A saving amount is (S(m)=300+40m) rupees. After how many months will the amount be (620) rupees?
#linear_growth
#solve_time
#savings
A (6)
B (7)
C (9)
D (8)
Explanation opens after your attempt
Step 1
Concept
From (300+40m=620), (40m=320) and (m=8). Form an equation to reach the target value.
Step 2
Why this answer is correct
The correct answer is D. (8). From (300+40m=620), (40m=320) and (m=8). Form an equation to reach the target value.
Step 3
Exam Tip
(300+40m=620) से (40m=320) और (m=8) मिलता है। लक्ष्य मान पाने के लिए समीकरण बनाएं।
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एक गोदाम में सामान (I(d)=200-12d) बचता है। कब सामान (80) बचेगा?
Items left in a warehouse are (I(d)=200-12d). When will (80) items be left?
#linear_decay
#word_problem
#solve_time
A (d=8)
B (d=9)
C (d=10)
D (d=12)
Explanation opens after your attempt
Step 1
Concept
From (200-12d=80), (12d=120) and (d=10). In decay set the remaining amount equal to the target.
Step 2
Why this answer is correct
The correct answer is C. (d=10). From (200-12d=80), (12d=120) and (d=10). In decay set the remaining amount equal to the target.
Step 3
Exam Tip
(200-12d=80) से (12d=120) और (d=10) मिलता है। क्षय में बची मात्रा को लक्ष्य के बराबर रखें।
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एक कक्षा में सदस्य (M(w)=32+2w) हैं। कितने सप्ताह बाद सदस्य (50) होंगे?
Members in a class are (M(w)=32+2w). After how many weeks will the members be (50)?
#linear_growth
#word_problem
#solve_time
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
From (32+2w=50), (2w=18) and (w=9). Form an equation for the target number.
Step 2
Why this answer is correct
The correct answer is C. (9). From (32+2w=50), (2w=18) and (w=9). Form an equation for the target number.
Step 3
Exam Tip
(32+2w=50) से (2w=18) और (w=9) है। लक्ष्य संख्या के लिए समीकरण बनाएं।
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यदि (U(t)=64-4t), तो (U(t)=28) कब होगा?
If (U(t)=64-4t), when will (U(t)=28)?
#linear_decay
#solve_time
#target
A (t=7)
B (t=8)
C (t=9)
D (t=10)
Explanation opens after your attempt
Step 1
Concept
From (64-4t=28), (4t=36) and (t=9). Move the subtraction term correctly in decay.
Step 2
Why this answer is correct
The correct answer is C. (t=9). From (64-4t=28), (4t=36) and (t=9). Move the subtraction term correctly in decay.
Step 3
Exam Tip
(64-4t=28) से (4t=36) और (t=9) मिलता है। क्षय में घटाव को सही दिशा में ले जाएं।
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यदि (T(t)=30+2t), तो (T(t)=46) कब होगा?
If (T(t)=30+2t), when will (T(t)=46)?
#linear_growth
#solve_time
#target
A (t=6)
B (t=8)
C (t=10)
D (t=16)
Explanation opens after your attempt
Step 1
Concept
From (30+2t=46), (2t=16) and (t=8). Solve the equation for the target value.
Step 2
Why this answer is correct
The correct answer is B. (t=8). From (30+2t=46), (2t=16) and (t=8). Solve the equation for the target value.
Step 3
Exam Tip
(30+2t=46) से (2t=16) और (t=8) मिलता है। लक्ष्य मान के लिए समीकरण हल करें।
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एक बैटरी (B(h)=100-8h) प्रतिशत बचती है। बैटरी (60%) कब होगी?
A battery remains (B(h)=100-8h) percent. When will the battery be (60%)?
#linear_decay
#solve_time
#battery
A (4) घंटे / (4) hours
B (5) घंटे / (5) hours
C (6) घंटे / (6) hours
D (8) घंटे / (8) hours
Explanation opens after your attempt
Correct Answer
B. (5) घंटे / (5) hours
Step 1
Concept
From (100-8h=60), (8h=40) and (h=5). In decay set the remaining value equal to the target.
Step 2
Why this answer is correct
The correct answer is B. (5) घंटे / (5) hours. From (100-8h=60), (8h=40) and (h=5). In decay set the remaining value equal to the target.
Step 3
Exam Tip
(100-8h=60) से (8h=40) और (h=5) मिलता है। क्षय में बचा हुआ मान लक्ष्य के बराबर रखें।
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एक बचत राशि (S(m)=200+50m) रुपये है। कितने महीनों बाद राशि (500) रुपये होगी?
A saving amount is (S(m)=200+50m) rupees. After how many months will the amount be (500) rupees?
#linear_growth
#solve_time
#savings
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
From (200+50m=500), (50m=300) and (m=6). Form an equation to reach the target value.
Step 2
Why this answer is correct
The correct answer is C. (6). From (200+50m=500), (50m=300) and (m=6). Form an equation to reach the target value.
Step 3
Exam Tip
(200+50m=500) से (50m=300) और (m=6) मिलता है। लक्ष्य मान पाने के लिए समीकरण बनाएं।
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