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A battery remains (B(h)=96-6h) percent. When will the battery be (48%)?

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Answer and explanation

Correct answer: 8

For the battery percentage to be 48, set \(B(h)=48\): \(96-6h=48\). Thus, \(6h=48\), so \(h=8\). Therefore, the battery will be 48% after 8 hours. At 6 hours, it is \(96-36=60\)% remaining, so that nearby option is incorrect. Exam tip: In a linear decay problem, equate the function to the target value and solve for the variable.

Related tags

Linear DecayLinear EquationsBattery PercentagePolynomialsAlgebra

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

For the battery percentage to be 48, set \(B(h)=48\): \(96-6h=48\). Thus, \(6h=48\), so \(h=8\). Therefore, the battery will be 48% after 8 hours. At 6 hours, it is \(96-36=60\)% remaining, so that nearby option is incorrect. Exam tip: In a linear decay problem, equate the function to the target value and solve for the variable.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.

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