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Class 9MathematicsIntroduction to PolynomialsLinear growth and decayEasyLevel 38
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If water left in a tank is (L(t)=60-3t) litres, how much water was there at (t=0)?

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Answer and explanation

Correct answer: 60 litres

To find the initial amount, put t=0: L(0)=60-3(0)=60 litres. Therefore, the correct answer is 60 litres. The value 57 litres is obtained at t=1, when 3 litres have already decreased. Exam tip: in a linear expression a+bt, the value at t=0 is the constant term a.

Related tags

PolynomialsLinear ExpressionInitial ValueLinear DecaySubstitution

Frequently asked questions

What is the correct answer to this question?

60 litres

Why is this the correct answer?

To find the initial amount, put t=0: L(0)=60-3(0)=60 litres. Therefore, the correct answer is 60 litres. The value 57 litres is obtained at t=1, when 3 litres have already decreased. Exam tip: in a linear expression a+bt, the value at t=0 is the constant term a.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear growth and decay.

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  2. 2If the amount of water is (W(t)=50-4t) litres, what type of change is it?
  3. 3In the linear rule (C(d)=15+2d), what is the initial value?
  4. 4In the linear rule (P(t)=80-5t), what is the rate of change per unit?
  5. 5If (S(t)=10+6t), what will be the value of (S(t)) at (t=4)?
  6. 6If (M(t)=90-7t), what is the value of (M(t)) at (t=5)?
  7. 7Books in a library increase according to (B(n)=100+8n). What does the coefficient of (n) show?
  8. 8Which rule represents linear growth?
  9. 9Which rule represents linear decay?
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